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Bunuel
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as 1 jin = 14 daks
so, 2 jin = 28 daks
area of square with 28 dak length \(= 28^2 = 784\)
area of square with 2 dak length = 4
total number od squares in large square \(= \frac{784}{4} = 196\)
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Your explanation, and by extension your approach, is straight forward. In my opinion this was a <35 second question, for which one ought to have a crystal clear picture of the required equations in mind.
hasnain3047
as 1 jin = 14 daks
so, 2 jin = 28 daks
area of square with 28 dak length \(= 28^2 = 784\)
area of square with 2 dak length = 4
total number od squares in large square \(= \frac{784}{4} = 196\)
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Bunuel
If a dak is a unit of length and 14 daks = 1 jin, how many squares with a side length of 2 daks can fit in a square with a side length of 2 jins?

(A) 14
(B) 28
(C) 49
(D) 144
(E) 196


1 jin = 14 daks hence 2 jin = 28 daks

Number of squares = Area of 28 square daks/ Area of 2 square daks
= 28*28/2*2
=196

Hence Option E solved in 30 seconds :-)
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Solution



Given:
    • dak is a unit of length and 14 daks = 1 jin

To find:
    • The number of squares with a side length of 2 daks can fit in a square with a side length of 2 jins

Approach and Working:
    • 2 Jins= 28 daks.
    • Hence, area of the square of the side length 2 jins= pi * \((28)^2\)
      o And, area of the square of the side length 2 daks= pi *\((2)^2\)= 4 pi

Let us assume that ‘n’ squares of side length 2 daks can fit in a square of side length 2 jins.
    • Hence, n* 4 pi= pi* \((28)^2\)
      o n= 196

Hence, the correct answer is option E.

Answer: E
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