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Math Expert V
Joined: 02 Sep 2009
Posts: 56372
If a dak is a unit of length and 14 daks = 1 jin, how many squares wit  [#permalink]

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Difficulty:   35% (medium)

Question Stats: 63% (01:31) correct 37% (01:15) wrong based on 85 sessions

### HideShow timer Statistics If a dak is a unit of length and 14 daks = 1 jin, how many squares with a side length of 2 daks can fit in a square with a side length of 2 jins?

(A) 14
(B) 28
(C) 49
(D) 144
(E) 196

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GMAT 1: 630 Q48 V28 GMAT 2: 540 Q49 V16 Re: If a dak is a unit of length and 14 daks = 1 jin, how many squares wit  [#permalink]

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Bunuel wrote:
If a dak is a unit of length and 14 daks = 1 jin, how many squares with a side length of 2 daks can fit in a square with a side length of 2 jins?

(A) 14
(B) 28
(C) 49
(D) 144
(E) 196

The area of square whose has length of 2 jin in each side is = 2j * 2j = 2*14 d * 2*14 d
The area of square whose has length of 2 ducks in each side is = 2d * 2d
Hence to tal square required : $$\frac{(2*14 d * 2*14 d)}{(2d * 2d)}$$ = $$14*14 =196$$
Hence Ans E
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Re: If a dak is a unit of length and 14 daks = 1 jin, how many squares wit  [#permalink]

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Bunuel wrote:
If a dak is a unit of length and 14 daks = 1 jin, how many squares with a side length of 2 daks can fit in a square with a side length of 2 jins?

(A) 14
(B) 28
(C) 49
(D) 144
(E) 196

No of squares=Area of the square with side length of 2 jins/Area of the square with side length of 2 daks

Area of the square with side length of 2 jins(=2*14 daks=28 daks)=28*28 square daks

Area of the square with side length of 2 daks=2*2=4 square daks

So , no of squares=$$\frac{28*28}{4}$$=196

Ans. (E)
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Re: If a dak is a unit of length and 14 daks = 1 jin, how many squares wit  [#permalink]

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3
as 1 jin = 14 daks
so, 2 jin = 28 daks
area of square with 28 dak length $$= 28^2 = 784$$
area of square with 2 dak length = 4
total number od squares in large square $$= \frac{784}{4} = 196$$
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Re: If a dak is a unit of length and 14 daks = 1 jin, how many squares wit  [#permalink]

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Your explanation, and by extension your approach, is straight forward. In my opinion this was a <35 second question, for which one ought to have a crystal clear picture of the required equations in mind.
hasnain3047 wrote:
as 1 jin = 14 daks
so, 2 jin = 28 daks
area of square with 28 dak length $$= 28^2 = 784$$
area of square with 2 dak length = 4
total number od squares in large square $$= \frac{784}{4} = 196$$

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Re: If a dak is a unit of length and 14 daks = 1 jin, how many squares wit  [#permalink]

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1
Bunuel wrote:
If a dak is a unit of length and 14 daks = 1 jin, how many squares with a side length of 2 daks can fit in a square with a side length of 2 jins?

(A) 14
(B) 28
(C) 49
(D) 144
(E) 196

1 jin = 14 daks hence 2 jin = 28 daks

Number of squares = Area of 28 square daks/ Area of 2 square daks
= 28*28/2*2
=196

Hence Option E solved in 30 seconds _________________
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Re: If a dak is a unit of length and 14 daks = 1 jin, how many squares wit  [#permalink]

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Solution

Given:
• dak is a unit of length and 14 daks = 1 jin

To find:
• The number of squares with a side length of 2 daks can fit in a square with a side length of 2 jins

Approach and Working:
• 2 Jins= 28 daks.
• Hence, area of the square of the side length 2 jins= pi * $$(28)^2$$
o And, area of the square of the side length 2 daks= pi *$$(2)^2$$= 4 pi

Let us assume that ‘n’ squares of side length 2 daks can fit in a square of side length 2 jins.
• Hence, n* 4 pi= pi* $$(28)^2$$
o n= 196

Hence, the correct answer is option E.

_________________ Re: If a dak is a unit of length and 14 daks = 1 jin, how many squares wit   [#permalink] 02 Sep 2018, 14:02
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