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02 Sep 2018, 23:14
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (01:58) correct
16%
(01:31)
wrong
based on 92
sessions
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A cylindrical can placed on a table leaves a water ring that is 10% larger than the circumference of the bottom of the can. If the area of the bottom of the can is 25π, which of the following is area encircled by the water ring?
A. \(121\pi\)
B. \(110\pi\)
C. \(55\pi\)
D. \(30.25\pi\)
E. \(11\pi\)
A. \(121\pi\)
B. \(110\pi\)
C. \(55\pi\)
D. \(30.25\pi\)
E. \(11\pi\)
saurabh9gupta
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02 Sep 2018, 23:19
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Shouldn't the answer be 30.25pi
Posted from my mobile device
Posted from my mobile device
25 pi = pi *r^2
r = 5
2*pi*r (circumference of can) = 10*pi
water ring that is 10% larger = 1.1(10*pi)
= 11*pi
2*pi*R = 11*pi
R= 11/2
The area is pi∗(11/2)^2 = 30.25*pi
Answer is D
Thanks PKN
r = 5
2*pi*r (circumference of can) = 10*pi
water ring that is 10% larger = 1.1(10*pi)
= 11*pi
2*pi*R = 11*pi
R= 11/2
The area is pi∗(11/2)^2 = 30.25*pi
Answer is D
Thanks PKN
