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MathRevolution
[Math Revolution GMAT math practice question]

If x and y are integers, what is the least possible positive value of 21x+35y?

A. 1
B. 3
C. 5
D. 7
E. 9

Another approach:

There's a nice rule that says:
If j, k and d are integers, and j is a multiple of d, and k is a multiple of d, then (j+k) must be a multiple of d

21x is a multiple of 7, since 21x = 7(3x)
35y is a multiple of 7, since 35y = 7(5y)

Since 21x and 35y are multiples of 7, the sum 21x + 35y must be a multiple of 7.
Since only 1 answer choice (D) is a multiple of 7, D must be the correct answer.

Cheers,
Brent
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=>

\(21x + 35y = 7*3x + 7*5y = 7(3x+5y)\) is a multiple of \(7\). The smallest positive multiple of \(7\) is \(7\). So, we look for \(x\) and \(y\) such that \(21x + 35y = 7\). This will occur when \(3x + 5y = 1\).
When \(x = 2\) and \(y = -1, 3x + 5y = 3*2 + 5*(-1) = 6 – 5 = 1\), and \(21x + 35y = 7(3x+5y) = 7(1) = 7.\)
Thus, \(7\) is the answer.

Therefore, the answer is D.
Answer: D
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MathRevolution
[Math Revolution GMAT math practice question]

If x and y are integers, what is the least possible positive value of 21x+35y?

A. 1
B. 3
C. 5
D. 7
E. 9

Since x and y are integers and 21x + 35y = 7(3x + 5y), we see that the answer must be a multiple of 7. Therefore, D is the correct answer.

Answer: D
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MathRevolution
[Math Revolution GMAT math practice question]

If x and y are integers, what is the least possible positive value of 21x+35y?

A. 1
B. 3
C. 5
D. 7
E. 9

Asked: If x and y are integers, what is the least possible positive value of 21x+35y?

21x + 35y = 7(3x + 5y)
3x + 5y has least possible positive value of 1; when x = 2; y = -1
21x + 35y = 7(3x + 5y) will have least possible positive value of 7

IMO D
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