If w widgets cost c cents, how many widgets can you get for d dollars?

Question

(A)  \frac{100dw}{c}

(B)  \frac{dw}{100c}

(C)  100cdw

(D)  \frac{dw}{c}

(E)  cdw

PKN · Answer

Unit cost of widgets= \frac{c}{w}  cents
Or,  \frac{c}{100w}  dollars are required to purchase 1 widget
Or, $1 is required to purchase  \frac{100w}{c} widgets
hence $d is required to purchase  \frac{100dw}{c}

Ans. (A)

varun4s · Answer

For c cents, w widgets can be bought

......1 cent..,  \frac{w}{c,}  widgets can be bought

.......100d cents....,  \frac{w}{c} *100d widgets can be bought

=  \frac{100dw}{c}

Answer: A.

Hero8888 · Answer

One of my favorite approaches for questions with all variables is plug-in method.

Let w=100 pcs, c=100 cents, d = $1 (actually d=c, so for 'd' we can buy the same number of 100 pcs - now we have to find an option that will give us the same 100 pcs.). Only option A gives us 100. Hence this is the right choice.

Now if you wonder how efficient this method is: 01:10 for the question above and I got the right answer, with my brain in a low level of energy consumption mode. Belive me, the saved brain stamina will be very useful for hard level questions later on the test. I highly recommend to use algebra only in cases in which it is really necessary.

Abhishek009 · Answer

1 Dollar = 100 Cents

So, d Dollar = 100 d Cents

For c cents w widgets can be bought

So, For 1 cents  \frac{w}{c}  widgets can be bought

Thus, for 100 d Cents  \frac{100dw}{c}  widgets can be bought, Answer must be (A)

09173140521 · Answer

can you explain this question in simple way ? a little confusing quantity or price and number of item

chrtpmdr · Answer

I dont get the multiplication by hundred
Does this mean the problem is based on the fact that you write C's as a non comma? Like 2 cents = 2 and not 0,02? 
I think that was my mistake

because I wrote it like W / C and said if C = 0,05 that means I can buy 20 widgets for one Dollar so D dollar give me D*20 widges

KarishmaB · Answer

We know

1 dollar = 100 cents

Simply use the unitary method:

c cents buys us w widgets

Then 1 cent buys us w/c widgets

Then, d dollars (= 100d cents) buys us (w/c)*100d widgets = 100dw/c widgets.

MathRevolution · Answer

'w' widgets = 'c' cents

1 cent:  \frac{w}{c}  widgets

1 dollar = 100 cents, hence multiplying both the sides by '100'

=> 100 cents =  \frac{w}{c}  * 100

=> 1 dollar =  \frac{100w }{c}

=> 'd dollars:  \frac{100dw }{c}

Answer A

ScottTargetTestPrep · Answer

We can let w = 2, c = 10, and d = 4.

Thus, 2 widgets cost 10 cents, or each widget costs 10/2 = 5 cents.

So for 400 cents, 400/5 = 80 widgets can be purchased.

Plugging these values back into answer choice A we have:

(100 x 4 x 2)/10 = 800/10 = 80, so answer A is correct.

bumpbot · Answer

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If w widgets cost c cents, how many widgets can you get for d dollars?

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If w widgets cost c cents, how many widgets can you get for d dollars?

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