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505-555 (Easy)|   Geometry|               
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Bunuel
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Given
AB||CE,
CE = DE, and
y = 45

As the CE = DE , Angle ECD = Angle EDC ( Consider Angle ECD = M )

Sum of all angle of triangle - ECD is 180, therefore Angle (ECD + EDC + CED ) = 180
2M + 45 = 180 = M = 67.5

Further, as AB||CE, Angle ECD = Angle ABC
Hence X= 67.5%
Answer
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Bunuel

In the figure above, if AB||CE, CE = DE, and y = 45, then x =

A. 45
B. 60
C. 67.5
D. 112.5
E. 135


Attachment:
GAMT_PS_1248.png

Since Y = 45 and the Line CE and DE are equal. Triangle CED is an isosceles triangle, which would mean Angle ECD and Angle EDC are equal.
Since Y is 45 and the sum of all angles of the triangle is 180.
Angle EDC + Angle ECD = 180 - 45 = 135
Angle EDC = Angle ECD = 67.5 (135/2)

Now Since Line AB and EC are parallel Angle ECD = Angle CBA = 67.5

Answer is C

Hope it helps a little
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I understand the concept of the isosceles triangles but in this case how are we supposed to be sure that the two angles that are equal within the triangle are angle ECD and angle EDC and not that there are two y's in the triangle?
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Bunuel

In the figure above, if AB||CE, CE = DE, and y = 45, then x =

A. 45
B. 60
C. 67.5
D. 112.5
E. 135


Attachment:
GAMT_PS_1248.png
Solution:

Since AB || CE, we see that triangles ABD and ECD are similar. Therefore, angle A = angle CED and angle B = angle ECD. Furthermore, since CE = DE, triangle ECD is an isosceles triangle, and angle ECD = angle CDE. Since we are given that angle CED = y = 45 degrees, then angles ECD and CDE are each (180 - 45) / 2 = 135/2 = 67.5 degrees. Since angle B = angle ECD, angle B = x = 67.5 degrees.

Answer: C
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