Bunuel
Which of the following CANNOT be a value of \(\frac{1}{x-1}\)?
A. -1
B. 0
C. 2/3
D. 1
E. 2
Alternatively, we can
test each answer choiceA) -1
Is it possible for 1/(x-1) to equal -1?
Let's find out.
We'll see if we can solve the equation: 1/(x-1) = -1
Multiply both sides by (x-1) to get: 1 = -1(x-1)
Expand right side: 1 = -x + 1
Solve: x = 0
So, when x = 0, 1/(x-1) = -1
Since 1/(x-1) CAN equal -1, we can ELIMINATE A
B) 0
Is it possible for 1/(x-1) to equal 0?
Let's find out.
We'll see if we can solve the equation: 1/(x-1) = 0
Multiply both sides by (x-1) to get: 1 = 0
Hmmmm.
Looks like 1/(x-1) CANNOT equal 0
At this point, I'd select B and move on.
But, for "kicks" let's keep going
C) 2/3
Start with the equation: 1/(x-1) = 2/3
Multiply both sides by (x-1) to get: 1 = (2/3)(x-1)
Expand right side: 1 = 2x/3 - 2/3
Add 2/3 to both sides: 5/3 = 2x/3
Multiply both sides by 3 to get: 5 = 2x
Solve: x = 2.5
So, when x = 2.5, 1/(x-1) = 2/3
Since 1/(x-1) CAN equal 2/3, we can ELIMINATE C
D) 1
Start with the equation: 1/(x-1) = 1
Multiply both sides by (x-1) to get: 1 = (1)(x-1)
Expand right side: 1 = x - 1
Add 1 to both sides: 2 = x
So, when x = 2, 1/(x-1) = 1
Since 1/(x-1) CAN equal 1, we can ELIMINATE D
E) 1
Start with the equation: 1/(x-1) = 2
Multiply both sides by (x-1) to get: 1 = (2)(x-1)
Expand right side: 1 = 2x - 2
Add 2 to both sides: 3 = 2x
Solve: x = 3/2
So, when x = 3/2, 1/(x-1) = 2
Since 1/(x-1) CAN equal 2, we can ELIMINATE E
Answer: E
Cheers,
Brent