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Bunuel Can you check the OA?

We are getting as B...
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Bunuel Can you check the OA?

We are getting as B...
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B is the OA. Edited. Thank you.
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See graphic approach to this question below. Lines will never cross the x-axis - function y will never = 0. Answer B




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Bunuel
Which of the following CANNOT be a value of \(\frac{1}{x-1}\)?

A. -1
B. 0
C. 2/3
D. 1
E. 2

In order for x/y to equal 0, we need x to equal 0

So, we can see that, in the fraction 1/(x - 1), the numerator does NOT equal zero.
This means that 1/(x - 1) CANNOT equal 0.

Answer: B

Cheers,
Brent
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Bunuel
Which of the following CANNOT be a value of \(\frac{1}{x-1}\)?

A. -1
B. 0
C. 2/3
D. 1
E. 2

Alternatively, we can test each answer choice

A) -1
Is it possible for 1/(x-1) to equal -1?
Let's find out.
We'll see if we can solve the equation: 1/(x-1) = -1
Multiply both sides by (x-1) to get: 1 = -1(x-1)
Expand right side: 1 = -x + 1
Solve: x = 0
So, when x = 0, 1/(x-1) = -1
Since 1/(x-1) CAN equal -1, we can ELIMINATE A

B) 0
Is it possible for 1/(x-1) to equal 0?
Let's find out.
We'll see if we can solve the equation: 1/(x-1) = 0
Multiply both sides by (x-1) to get: 1 = 0
Hmmmm.
Looks like 1/(x-1) CANNOT equal 0

At this point, I'd select B and move on.
But, for "kicks" let's keep going

C) 2/3
Start with the equation: 1/(x-1) = 2/3
Multiply both sides by (x-1) to get: 1 = (2/3)(x-1)
Expand right side: 1 = 2x/3 - 2/3
Add 2/3 to both sides: 5/3 = 2x/3
Multiply both sides by 3 to get: 5 = 2x
Solve: x = 2.5
So, when x = 2.5, 1/(x-1) = 2/3
Since 1/(x-1) CAN equal 2/3, we can ELIMINATE C

D) 1
Start with the equation: 1/(x-1) = 1
Multiply both sides by (x-1) to get: 1 = (1)(x-1)
Expand right side: 1 = x - 1
Add 1 to both sides: 2 = x
So, when x = 2, 1/(x-1) = 1
Since 1/(x-1) CAN equal 1, we can ELIMINATE D

E) 1
Start with the equation: 1/(x-1) = 2
Multiply both sides by (x-1) to get: 1 = (2)(x-1)
Expand right side: 1 = 2x - 2
Add 2 to both sides: 3 = 2x
Solve: x = 3/2
So, when x = 3/2, 1/(x-1) = 2
Since 1/(x-1) CAN equal 2, we can ELIMINATE E

Answer: E

Cheers,
Brent
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Bunuel
Which of the following CANNOT be a value of \(\frac{1}{x-1}\)?

A. -1
B. 0
C. 2/3
D. 1
E. 2

Recall that zero divided by a nonzero quantity is zero. However, we see that the numerator of the given expression is not zero and can never be zero, therefore, its value cannot be zero.

Answer: B
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Bunuel
Which of the following CANNOT be a value of \(\frac{1}{x-1}\)?

A. -1
B. 0
C. 2/3
D. 1
E. 2
\(\frac{Numerator}{Denominator} = 0\), possible only when the Numerator itself is 0 , since if the denominator is 0 the result will be undefined, hence Answer must be (B)
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The only way a fraction can equal 0 is if its numerator is 0.

Therefore, since the numerator in the given expression is not 0, the fraction cannot equal 0, no matter its denominator.
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Here's the key approach:

The question asks which value \(\frac{1}{x-1}\) cannot equal. So, we need to test each answer choice by setting up the equation \(\frac{1}{x-1} = \text{[each value]}\) and solving for \(x\). If we can find a valid \(x\), that value is possible. If we hit a contradiction or an invalid \(x\), that value is impossible.

Let's test a couple of choices to see the pattern:

Choice A: Can \(\frac{1}{x-1} = -1\)?

Setting up: \(\frac{1}{x-1} = -1\)

Multiply both sides by \((x-1)\): \(1 = -1(x-1)\)

Simplify: \(1 = -x + 1\)

Solve: \(0 = -x\), so \(x = 0\)

Check: When \(x = 0\), we get \(\frac{1}{0-1} = \frac{1}{-1} = -1\) ✓

So \(-1\) is possible.

Choice D: Can \(\frac{1}{x-1} = 1\)?

Setting up: \(\frac{1}{x-1} = 1\)

Multiply both sides by \((x-1)\): \(1 = x - 1\)

Solve: \(x = 2\)

Check: When \(x = 2\), we get \(\frac{1}{2-1} = 1\) ✓

So \(1\) is possible.

Now here's the critical insight you need to see:

Choice B: Can \(\frac{1}{x-1} = 0\)?

Think about what it takes for a fraction to equal zero. The only way a fraction equals zero is if the numerator is zero (while the denominator is non-zero).

But look at our expression \(\frac{1}{x-1}\) — the numerator is always \(1\), which is never zero.

Let's verify algebraically:

Setting up: \(\frac{1}{x-1} = 0\)

Multiply both sides by \((x-1)\): \(1 = 0(x-1)\)

Simplify: \(1 = 0\)

This is a mathematical contradiction! There's no value of \(x\) that can make this true.

Answer: B

The expression \(\frac{1}{x-1}\) can never equal \(0\) because that would require the numerator to be zero, which is impossible when the numerator is the constant \(1\).

You can verify that choices C and E are also possible by testing them the same way.

Want to master this concept completely?

The full solution on Neuron shows you how to test all five choices systematically, reveals the broader pattern for identifying impossible values of rational expressions, and teaches you time-saving techniques for spotting the answer quickly. You can check out the detailed step-by-step solution on Neuron by e-GMAT to understand how this concept applies to similar GMAT problems. You can also practice with comprehensive solutions for many other official questions on Neuron with detailed analytics to track your progress.

Hope this helps! Let me know if you have questions.
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The only way a number can be 0 is if the numerator is 0, hence B
Bunuel
Which of the following CANNOT be a value of \(\frac{1}{x-1}\)?

A. -1
B. 0
C. 2/3
D. 1
E. 2
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