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Draw a perpendicular towards x axis X'. BX' = 4 units ; AX' = 3 units. AB = 5 units.
Now check the distance of B from C using the points in the options.

a) 10 units
b) 10 units
c) sqrt 98
d) 10 units
e) 10 units
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Please somebody could put the answer?, I'm trying to figure out how can I solve it.
I got it we have to draw imaginary triangles with coordinates of C.

Thank you
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Please somebody could put the answer?, I'm trying to figure out how can I solve it.
I got it we have to draw imaginary triangles with coordinates of C.

Thank you

Use the options to solve it. Without it , it would take way to long.

You'll have to use assume C(x,y) and find the values for x and y

\((3-x)^2 + (4-y)^2 = 10^2\)
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jorgetomas9
Please somebody could put the answer?, I'm trying to figure out how can I solve it.
I got it we have to draw imaginary triangles with coordinates of C.

Thank you

Use the options to solve it. Without it , it would take way to long.

You'll have to use assume C(x,y) and find the values for x and y

\((3-x)^2 + (4-y)^2 = 10^2\)
Yes, I did it, Thank you.
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Bunuel : Can you pls help understand why it is C and not D?
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Bunuel : Can you pls help understand why it is C and not D?

The formula to calculate the distance between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\).

The distance between (10, 11) and (3, 4) is \(7\sqrt{2}\), while the distance between (11, 10) and (3, 4) is 10.
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