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Gegeyan

Avg speed = total distance/total time

D = V * T

D1 = V1 * T1

D1 = D2 because of the same distance.

D1 = D2 = V2 * T2

T1 = D1/V1

We know that D1 = D2 because it is a total of 60 miles trip and 30 was already completed. This leaves us with another 30 miles.

The equation becomes

avg speed = D1 + D1= 2D1/(D1/V1 + D1/V2)

This then becomes

2D1/ ((V1*D1 + D1*V2)/(V1*V2)

2D1 * (V1*V2)/(D1(V1+V2)

The D1 cancels and becomes 2*V1*V2/(V1+V2)

I hope it is clear now. Let me know if it helps!

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Salsanousi
Gegeyan

Avg speed = total distance/total time

D = V * T

D1 = V1 * T1

D1 = D2 because of the same distance.

D1 = D2 = V2 * T2

T1 = D1/V1

We know that D1 = D2 because it is a total of 60 miles trip and 30 was already completed. This leaves us with another 30 miles.

The equation becomes

avg speed = D1 + D1= 2D1/(D1/V1 + D1/V2)

This then becomes

2D1/ ((V1*D1 + D1*V2)/(V1*V2)

2D1 * (V1*V2)/(D1(V1+V2)

The D1 cancels and becomes 2*V1*V2/(V1+V2)

I hope it is clear now. Let me know if it helps!

Posted from my mobile device


Thank you so much! Your explanation is clear and helpful! :thumbup: :thumbup: :thumbup: :thumbup: :thumbup: :thumbup: :thumbup:
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Another approach:
Total d = 60mi
Total t = 60/50 = 6/5 hours --> 72 minutes
72 minutes - time take to ride the first 30 miles = time take to ride the remaining 30 miles
t1= 30/60 = 1/2 hour --> 30 minutes
72 - 30 = 42 minutes --> 46/60 hours
average speed of the second part of the trip = 30mi / (42/60)hrs = 3000/7 which equal approximately 43 minutes.

Hope it helps!­
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