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16 Oct 2018, 01:06
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
86% (01:04) correct
14%
(01:16)
wrong
based on 61
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The circle shown has center T. The measure of angle TVU is 60°. If the circle has a radius of 3, what is the length of segment RS?
A. 2
B. \(2 \sqrt{2}\)
C. 3
D. \(3 \sqrt{3}\)
E. \(6 \sqrt{2}\)
Attachment:
circle.jpg [ 9.34 KiB | Viewed 4787 times ]
Bunuel
TVU is an equilateral triangle(TU=TV=radius, angle TUV=angle TUV=60, angle UTV=180-60-60=60)
Note:- The Angles subtended by same arc at the circumference are equal. So, under arc SV, Angle SRV=angle SUV or TUV=60.
Now, join SV. RSV is a right angled triangle(60-90-30)
Hence the sides are in the ratio, SV:RV:RS= √3x:2x:x
RS=2x=6 or x=3
Therefore, RS=x=3
Ans. (C)
Edit:- I don't know why I took radius=2 instead of 3.. drinking
16 Oct 2018, 09:43
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TU = TV = 60 each. Therefore it's an equilateral triangle.
RTS = 60 (opposite angle)
RT = ST = 60 each. Therefore it's an equilateral triangle.
RT = radius = 3 = RS
Ans C
PKN , 2x = 6 ; not 4
RTS = 60 (opposite angle)
RT = ST = 60 each. Therefore it's an equilateral triangle.
RT = radius = 3 = RS
Ans C
PKN , 2x = 6 ; not 4
