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Sub 505 (Easy)|   Geometry|      
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pushpitkc
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What is the area of the circular region with center O shown in the Updated on: 02 Nov 2018, 04:23
Originally posted by pushpitkc on 02 Nov 2018, 04:22.
Last edited by Bunuel on 02 Nov 2018, 04:23, edited 1 time in total.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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5% (low)

Question Stats:

92% (01:02) correct 8% (01:17) wrong based on 143 sessions

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What is the area of the circular region with center O shown in the figure above?

(A) 100 Π
(B) 900 Π
(C) 1,600 Π
(D) 2,500 Π
(E) 4,900 Π


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GeometryProblem.PNG
GeometryProblem.PNG [ 11.91 KiB | Viewed 5105 times ]
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D
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vishumangal
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What is the area of the circular region with center O shown in the 02 Nov 2018, 04:38
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Length of the radius would be 50, Thus area will be 2500pi

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KHow
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What is the area of the circular region with center O shown in the 17 Jan 2019, 07:19
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Is there a specific formula used for obtaining 50 as the result for the radius (for this and other more advanced versions of this problem)?
Thanks!
vishumangal
Length of the radius would be 50, Thus area will be 2500pi

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philipssonicare
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What is the area of the circular region with center O shown in the 19 Jan 2019, 19:08
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KHow
Pythagorean formula can be used (hypotenuse).
Distance of a line formula can be used (which is just pythagorean formula really)

Giving the thread a bump in case there are others!
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Abhishek009
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What is the area of the circular region with center O shown in the 20 Jan 2019, 08:50
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pushpitkc


What is the area of the circular region with center O shown in the figure above?

(A) 100 Π
(B) 900 Π
(C) 1,600 Π
(D) 2,500 Π
(E) 4,900 Π


Show Spoiler
Attachment:
GeometryProblem.PNG
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Distance from the center to the point is \(\sqrt{( 40 - 0 )^2 + ( 30 - 0 )^2} = 50\)

So, Area of the circle is \(50^2Π = 2,500 Π\) , thus Answer must be (D)
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AntonioGalindo
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What is the area of the circular region with center O shown in the 26 Jan 2023, 11:32
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Bunuel, can you explain this question to me in a more elaborate manner, please?
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