Two dice, each with six sides numbered 1 through 6, are tossed. What

Question

Two dice, each with six sides numbered 1 through 6, are tossed. What is the probability that both dice will come up with either a 1 or a 2 ?

A. 1/36
B. 1/18
C. 1/9
D. 1/3
E. 2/3

Archit3110 · Answer

either 1 or 2 in first dice : 2/6
Either 1 or 2 in second dice : 2/6

2/6*2/6=1/9 option c

Shbm · Answer

both dice coming up with the number 1 - 1/6*1/6=1/36
 
both dice coming up with number 2 - 1/6*1/6=1/36

Since it is an 'OR' problem we need to add them both so 1/36+1/36=2/36=1/18

Answer is B

EgmatQuantExpert · Answer

Solution 
  Given:  
 • Two dice, each with six sides numbered 1 through 6, are tossed

To find:  
 • The probability that both dice will come up either 1 or 2

Approach and Working:   
 • P(both 1) =  \frac{1 * 1}{6 * 6} = \frac{1}{36} 
• P(both 2) =  \frac{1 * 1}{6 * 6} = \frac{1}{36} 
• P( a 1 and a 2) =  \frac{1 * 1}{6 * 6} = \frac{1}{36} 
• P( a 2 and a 1) =  \frac{1 * 1}{6 * 6} = \frac{1}{36}

Thus, P( either 1 or 2) =  \frac{1}{36} + \frac{1}{36} + \frac{1}{36} + \frac{1}{36} = \frac{4}{36} = \frac{1}{9}

Hence, the correct answer is Option C

Answer: C

https://e-gmat.com/blogs/wp-content/uploads/2018/08/Ability-Quiz-AT-e1533292152363.png

Shbm · Answer

If this is the right answer then I'm afraid but the question hasn't been worded properly. It clearly mentions that the number on both dice should be either a 1 or a 2. That means both the dice should have either 1 or either 2 and not like 1 in the first and 2 in the second one.

Archit3110 · Answer

Shbm  : I also got the question wrong , the wording of this question is not clear.

ankit9291 · Answer

Either 1 or 2 means

1,2
2,1
1,1
2,2

So 4/36

Posted from my mobile device

Shbm · Answer

yea same for me. However, don't worry such a poorly worded question wouldn't appear on the GMAT.

dabaobao · Answer

Possible Cases:
1,1
1,2
2,1
2,2
Therefore, 4 possible cases.
Total cases = 6 x 6 = 36
Probability = 4/36 = 1/9

BrentGMATPrepNow · Answer

P(both dice will come up with either a 1 or a 2) = P(1st die is 1 or 2   AND   2nd die is 1 or 2)
= P(1st die is 1 or 2)   x   P(2nd die is 1 or 2)
= 2/6   x   2/6
= 1/3   x   1/3
= 1/9

Answer: C

Cheers,
Brent

MWithrock · Answer

would it be correct to say that each dice has a 1/3 chance of getting a desired number so...

1/3*1/3 = 1/9?

ScottTargetTestPrep · Answer

Since each die has 6 outcomes, there are a total of 6 x 6 = 36 outcomes when two dice are rolled.

Of these 36 outcomes, (1, 1), (1, 2), (2, 1) and (2, 2) are the only ones in which both dice show either a 1 or a 2. Therefore, the probability is 4/36 = 1/9.

Answer: C

AVMachine · Answer

Favorable Cases are 2 (1 or 2).

So for Two Dices: (2C1/6C1) * (2C1/6C1) = 1/9.

BrushMyQuant · Answer

Two dice, each with six sides numbered 1 through 6, are tossed

As we are rolling 2 dice => Number of cases =  6^2  = 36

What is the probability that both dice will come up with either a 1 or a 2

Lets write down the possible cases 
(1,1), (1,2)
(2,1), (2,2)
=> 4 cases

=>  Probability (Both dice will come up with either a 1 or a 2)  =  \frac{4}{36}  =  \frac{1}{9}

So,  Answer will be C 
Hope it helps!

Playlist on Solved Problems on Probability  here

Watch the following video to MASTER Dice Rolling Probability Problems

https://www.youtube.com/watch?v=5PVZYQXet18

dhruvie · Answer

Total combinations:  36  - (1,1); (1,2); (1,3); ... ; (6,6)

Favourable:  4  - (1,1); (1,2); (2,1); (2,2)

Probability:  \frac{4}{36}  i.e.  \frac{1}{9}

Two dice, each with six sides numbered 1 through 6, are tossed. What

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