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CAMANISHPARMAR
Attachment:
CGEO.jpg

Which of the following is NOT a point on the circle of radius 5 and center O as graphed above?

(A) (-1, 2)
(B) (8, -1)
(C) (0, -5)
(D) (6, 3)
(E) (7, -6)

The general formula of a circle:

(x-h)^2 + (y-k)^2 = r^2....where h & k are coordinates of the origin.

Using center above:

(x-3)^2 + (y+1)^2 = 5^2

Apply as Brent says above:

(E) (7, -6).......(7-3)^2 + (-6+1)^2 = 16 + 25 = 31.........So it does NOT belong to the circle

Answer: E
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CAMANISHPARMAR

Which of the following is NOT a point on the circle of radius 5 and center O as graphed above?

(A) (-1, 2)
(B) (8, -1)
(C) (0, -5)
(D) (6, 3)
(E) (7, -6)
Let´s translate the x axis 1 unit down ("y" goes "y+1") and the y axis 3 units to the right ("x" goes "x-3")

Doing so, the center of the circle given is now at the origin(!) and "extremal points" are re-coordenated as shown:



(A) (-1,2) goes to (-4,3)
(B) (8,-1) goes to (5, 0)
(C) (0,-5) goes to (-3, -4)
(D) (6,3) goes to (3,4)
(E) (7, -6) goes to (4, -5)

It is clear that point (4,-5) does not belong to the given circle!

(It is also clear that all other points are on the circumference of the given circle... think about 3,4,5!)

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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CAMANISHPARMAR

Which of the following is NOT a point on the circle of radius 5 and center O as graphed above?

(A) (-1, 2)
(B) (8, -1)
(C) (0, -5)
(D) (6, 3)
(E) (7, -6)


Attachment:
CGEO.jpg
Solution:

The standard form of a circle with center (h, k) and radius r is (x - h)^2 + (y - k)^2 = r^2. Thus, we see that the equation of the given circle, with center (3, -1) and radius 5, will have the equation:


(x - 3)^2 + (y + 1)^2 = 25

If a point (a, b) is on circle O, then it will satisfy the above equation.

Of all the points given in the answer choices, (7, -6) is not on circle O since:

(7 - 3)^2 + (-6 + 1)^2 = 4^2 + (-5)^2 = 16 + 25 = 41 ≠ 25

Answer: E
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