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09 Dec 2018, 23:48
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
67% (01:26) correct
33%
(01:43)
wrong
based on 232
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The sum of n numbers is greater than 48. If the average (arithmetic mean) of the n numbers is 1.2, what is the least possible value of n?
A. 38
B. 39
C. 40
D. 41
E. 42
A. 38
B. 39
C. 40
D. 41
E. 42
09 Dec 2018, 23:53
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When the average is given, the total sum is the average times the number of objects ( whose average is given).
Sum of n numbers = n*(Average of n numbers)
=1.2n
1.2n>48
n>40
Hence n has to be greater than 40, so least value (among the options given) is 41.
Hence Option (D) is our choice.
Best,
Gladi
Sum of n numbers = n*(Average of n numbers)
=1.2n
1.2n>48
n>40
Hence n has to be greater than 40, so least value (among the options given) is 41.
Hence Option (D) is our choice.
Best,
Gladi
Bunuel
09 Dec 2018, 23:58
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Bunuel
Average = 1.2
As per the question ,
n * 1.2 > 48
n > 40.
The least value of n is 41.
