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Jazzmin
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A coin bank with nickels, dimes and quarters contains coins worth $35. 25 Dec 2018, 14:11
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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55% (hard)

Question Stats:

67% (02:59) correct 33% (03:24) wrong based on 137 sessions

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A coin bank with nickels, dimes and quarters contains coins worth $35.80. If there are twice as many nickels as there are dimes, and 10 more quarters than dimes, how many nickels are there? (Note - 1 Nickel =5 cents, 1 dime = 10 cents and 1 quarter =25 cents)
a. 186
b. 148
c. 96
d. 55
e. 48
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B
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A coin bank with nickels, dimes and quarters contains coins worth $35. 25 Dec 2018, 19:41
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Jazzmin
A coin bank with nickels, dimes and quarters contains coins worth $35.80. If there are twice as many nickels as there are dimes, and 10 more quarters than dimes, how many nickels are there? (Note - 1 Nickel =5 cents, 1 dime = 10 cents and 1 quarter =25 cents)
a. 186
b. 148
c. 96
d. 55
e. 48
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Let the numbers be nickels n, dime d and quarter q..
So total we have is 35.80$ or 3580 cents..
Now
n=2d,
q=10+d,
5n+10d+25q=3580
Substitute the values of n and q in terms of d in this equation..
5*2d+10d+25(10+d)=3580.......10d+10d+250+25d=3580
45d=3580-250=3330.....
\(d=\frac{3330}{45}=74\)
If d is 74, n is 2*d=2*74=148..
B
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A coin bank with nickels, dimes and quarters contains coins worth $35. 25 Dec 2018, 19:48
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Suppose there is x number of dimes.
Hence the number of nickels=2x and quarters=x+10
The eqn: 5*2x +10*x +25(x+10)=3580
or 45x+250=3580
or x=74
Thus 2x=148..........Hence Ans B
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A coin bank with nickels, dimes and quarters contains coins worth $35. 26 Dec 2018, 10:43
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Solution



Given:
    • A coin bank with nickels, dimes and quarters contains coins worth $35.80
    • There are twice as many nickels as there are dimes, and 10 more quarters than dimes
    • 1 Nickel = 5 cents, 1 dime = 10 cents and 1 quarter = 25 cents

To find:
    • The number of nickels present in the coin bank

Approach and Working:
As we have both nickels and quarters expressed in terms of dimes, let us assume that the number of dimes is n.
    • Hence, the number of nickels = 2 x n = 2n
    • And, the number of quarters = 10 + n

The total value worth of all three types of coins = [n x 10 + 2n x 5 + (10 + n) x 25] cents = (10n + 10n + 25n + 250) cents = (45n + 250) cents

Therefore, we can write
    • 45n + 250 = 3580
    Or, 45n = 3580 – 250
    Or, 45n = 3330
    Or, n = 74

Therefore, the number of nickels = 74 x 2 = 148

Hence, the correct answer is option B.

Answer: B

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A coin bank with nickels, dimes and quarters contains coins worth $35. 08 Jan 2022, 05:20
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Use the Plug-In Method.

Start with C: 96 nickles.

96 nickles = $4.80
48 dimes (since we have twice as many nickles as dimes) = $4.80
58 quarters (since we have 10 more than dimes) = $14.50

--> The sum is too little.
--> Continue with A: 186

You will then see, that the sum is too big. Therefore, the answer MUST be between A and C, so the right answer will be B.
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A coin bank with nickels, dimes and quarters contains coins worth $35. 29 Aug 2025, 14:08
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