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Bunuel
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We are given that a fair coin is tossed and a fair dice is rolled and We need to find What is the probability of turning up a heads and a 6?

Probability (Getting a Head and a 6) = P(H) * P(6) = \(\frac{1}{2}\) * \(\frac{1}{6}\) (As there is 1 out of 6 ways in which we can get a 6 out of 1 to 6)

= \(\frac{1}{12}\)

So, Answer will be B
Hope it helps!

Watch the following video to learn How to Solve Probability with Coin Toss Problems


Watch the following video to learn How to Solve Dice Rolling Probability Problems

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1/2 * 1/6 = 1/12

multiply the numerator by the numerator and the denominator by the denominator
Bunuel
The probability is 1/2 that a coin will turn up heads on any given toss and the probability is 1/6 that a number cube with faces numbered 1 to 6 will turn up any particular number. What is the probability of turning up a heads and a 6?

(A) 1/36
(B) 1/12
(C) 1/6
(D) 1/4
(E) 2/3
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