Bob has a 24-sided die with an integer between 1 and 24 on each face.

Question

Bob has a 24-sided die with an integer between 1 and 24 on each face. Every number is featured exactly once. When he rolls, what is the probability that the number showing is a factor of 24?

(A) 1/3
(B) 1/8
(C) 5/36
(D) 1/6
(E) 7/36

UB001 · Answer

Factors of 24 = 1,2,3,4,6,8,12,24 Total 8 No.s
8/24 = 1/3

Answer Option A is Correct

Archit3110 · Answer

factor of 24 = 2^3 * 3^1 = (3+1)*(1+1) = 8
8/24 = 
1/3 
IMO A

BrushMyQuant · Answer

Bob has a 24-sided die with an integer between 1 and 24 on each face. Every number is featured exactly once.

As we are rolling a 24 sided die => Number of cases = 24

When he rolls, what is the probability that the number showing is a factor of 24?

Lets write the factors of 24, they are
1, 2, 3, 4, 6, 8, 12, 24
=> 8 cases
 
 this video  to  MASTER Factors and Multiples  ]

P(Factor of 24)  =  \frac{8}{24}  =  \frac{1}{3}

So,  Answer will be A 
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

https://www.youtube.com/watch?v=5PVZYQXet18

Bob has a 24-sided die with an integer between 1 and 24 on each face.

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Problem Solving (PS) Questions

Bob has a 24-sided die with an integer between 1 and 24 on each face.

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards