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Bunuel
Upon winning the lottery, John spent 1/3 of his winnings on a home and 1/4 of the remaining amount on a car. After these purchases, he had $200,000 left. How much money did John win in the lottery?


A 400,000

B 480,000

C 600,000

D 800,000

E 2,400,000

We can let n = the amount of money he won and create the equation:

n/3 + (1/4)(n - n/3) + 200,000 = n

n/3 - (1/4)(2n/3) + 200,000 = n

Multiplying the entire by 12, we have:

4n + 2n + 2,400,000 = 12n

2,400,000 = 6n

400,000 = n

Alternate Solution:

After spending 1/3 of the money, he is left with 2/3 of the prize and after spending 1/4 of this amount, he is left with 2/3 x 3/4 = 2/4 = 1/2; i.e. half of the prize money. If the remaining amount of 200,000 is half of what he had to begin with, then he won 200,000 x 2 = $400,000.

Answer: A
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Bunuel
Upon winning the lottery, John spent 1/3 of his winnings on a home and 1/4 of the remaining amount on a car. After these purchases, he had $200,000 left. How much money did John win in the lottery?


A 400,000

B 480,000

C 600,000

D 800,000

E 2,400,000


Let the amount he won be x

Home=1/3*x
Car=1-x/3*1/4=2x/12=x/6


x-x/3-x/6=200000
3x/6=200000
x=400000
A
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Let the lottery amount won by John was 120 ( Assume an initial value for simple calculation. Usually, it is better to assume 100, but in the question, as we have \(\frac{1}{3}\) and \(\frac{1}{4}\), take LCM of 3 and 4 that is 12 and assume the lottery amount to be 120)

John spent \(\frac{1}{3}\) of his winnings on a home : \(\frac{1}{3}\) *120 = 40 (spent) ----> Remaining 120-40 = 80.
John spent \(\frac{1}{4}\) of the remaining amount on a car: \(\frac{1}{4}\) * 80 = 20 (Spent) -----> Remaining = 60.

Initial amount --------> Remaining amount
120 --------> 60
? --------> $200,000 (Given in the question)

? = 120 * 200,000 / 60 = $400,000

Answer A


Short Approach:

John total spending : \(\frac{1}{3}\) +\(\frac{2}{12}\)=\(\frac{6}{12}\) = \(\frac{1}{2}\). [ After \(\frac{1}{3}\) spending John is left with \(\frac{2}{3}\) of amount out of which he spends \(\frac{1}{4}\) that is \(\frac{2}{3}\)*\(\frac{1}{4}\) = \(\frac{2}{12}\)

He is left with \(\frac{1}{2}\) which is $200,000.

Therefore, \(\frac{1}{2}\) * Total lottery amount = $200,000

Total lottery amount = $400,000

Answer A
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3/4th of the 2/3 remaining is 200000
i.e 1/2 is 200000

Therefore, full amount will be 400000
Option A
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