Let the lottery amount won by John was 120 ( Assume an initial value for simple calculation. Usually, it is better to assume 100, but in the question, as we have \(\frac{1}{3}\) and \(\frac{1}{4}\), take LCM of 3 and 4 that is 12 and assume the lottery amount to be 120)
John spent \(\frac{1}{3}\) of his winnings on a home : \(\frac{1}{3}\) *120 = 40 (spent) ---->
Remaining 120-40 = 80.John spent \(\frac{1}{4}\) of the remaining amount on a car: \(\frac{1}{4}\) * 80 = 20 (Spent) ----->
Remaining = 60. Initial amount --------> Remaining amount 120 --------> 60
? --------> $200,000 (Given in the question)
? = 120 * 200,000 / 60 = $400,000Answer AShort Approach: John total spending : \(\frac{1}{3}\) +
\(\frac{2}{12}\)=\(\frac{6}{12}\) = \(\frac{1}{2}\). [ After \(\frac{1}{3}\) spending John is left with \(\frac{2}{3}\) of amount out of which he spends \(\frac{1}{4}\) that is \(\frac{2}{3}\)*\(\frac{1}{4}\) =
\(\frac{2}{12}\) He is left with \(\frac{1}{2}\) which is $200,000.
Therefore, \(\frac{1}{2}\) * Total lottery amount = $200,000
Total lottery amount = $400,000Answer A