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13 Feb 2019, 00:21
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
79% (02:07) correct
21%
(02:06)
wrong
based on 99
sessions
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A line passes through the points (–2, 2) and (–1, –3). At what point does this line intersect the line with the equation y = x - 8?
(A) (–5, 3)
(B) (0, –8)
(C) (–3, 5)
(D) (3/5, 14/3)
(E) (8/3, 16/3)
(A) (–5, 3)
(B) (0, –8)
(C) (–3, 5)
(D) (3/5, 14/3)
(E) (8/3, 16/3)
Archit3110
Major Poster
13 Feb 2019, 04:11
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Bunuel
eqn of line (–2, 2) and (–1, –3) = y=-5/2x-3
which means its -ve slope and y intercept =-3
also for given line y = x - 8; slope is +ve and y intercept is -8
now for two lines to intersect means they would have to be perpendicular to each other or say thier slope product should be -1
if we plot the points we observe that the only possible quadrant these two lines can meet is IV i.e x is +ve and y -ve
so only option B suffices
IMO B
14 May 2019, 03:00
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My approach:
Equation of the line passing through the points (-2,2) and (-1,-3) is
y-2=-5(x+2)
y=-8-5x------- (1)
y=-8+x--------(2) (Given)
(1)-(2)=> x=0
Substituting x=0 in (2) y=-8
(0,-8) IMO B
Equation of the line passing through the points (-2,2) and (-1,-3) is
y-2=-5(x+2)
y=-8-5x------- (1)
y=-8+x--------(2) (Given)
(1)-(2)=> x=0
Substituting x=0 in (2) y=-8
(0,-8) IMO B
