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Bunuel
If \(a = (0.404)^3\), \(b = \sqrt[3]{0.404}\), and \(c = 0.404\), then which of the following is true?

A. a > b > c
B. b > a > c
C. a > c > b
D. c > a > b
E. b > c > a

\(a^3 = (0.404)^6\) , \(b^3 =0.404\) & \(c^3 = (0.404)^3\)

Thus, Answer must be b > c > a (E)
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To compare the values of a, b, and c, let's calculate each of them:

a = (0.404)^3 ≈ 0.06553664
b = 0.404^(1/3) ≈ 0.74637998
c = 0.404

Now, let's compare them:

b > c > a

So, the correct order is:

E. b > c > a
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