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Bunuel
Carol buys x widgets at a cost of y cents per widget. She packages them, q widgets per box, and sells them at a price of z dollars per box. What is the amount of profit, in dollars, that she makes on the sale (profit = sales revenue − cost)?


A. 100qz − xy

B. xz/q - xy/100

C. qz - xy/100

D. 100z/q - xy

E. xz/q - xy

Cost price = x * y/100 = xy/100

Number of boxes = x/q

Selling price = xz/q

Profit = xz/q - xy/100.

B is the correct answer.

C is the correct answer.
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cost of widgets
x*y/100
boxes x/q
SP = x*z/q
so profit

xz/q - xy/100
IMO B


Bunuel
Carol buys x widgets at a cost of y cents per widget. She packages them, q widgets per box, and sells them at a price of z dollars per box. What is the amount of profit, in dollars, that she makes on the sale (profit = sales revenue − cost)?


A. 100qz − xy

B. xz/q - xy/100

C. qz - xy/100

D. 100z/q - xy

E. xz/q - xy
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Bunuel
Carol buys x widgets at a cost of y cents per widget. She packages them, q widgets per box, and sells them at a price of z dollars per box. What is the amount of profit, in dollars, that she makes on the sale (profit = sales revenue − cost)?


A. 100qz − xy

B. xz/q - xy/100

C. qz - xy/100

D. 100z/q - xy

E. xz/q - xy


Given:
1. Carol buys x widgets at a cost of y cents per widget.
2. She packages them, q widgets per box, and sells them at a price of z dollars per box.

Asked: What is the amount of profit, in dollars, that she makes on the sale (profit = sales revenue − cost)?

1. Carol buys x widgets at a cost of y cents per widget.
Cost price for x widgets = xy cents = $xy/100

2. She packages them, q widgets per box, and sells them at a price of z dollars per box.
Number of boxes = x/q boxes
Sales revenue = $ (x/q) * z = $ xz/q

Profit = Sales - Cost
= $ (xz/q - xy/100)

IMO B
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Bunuel
Carol buys x widgets at a cost of y cents per widget. She packages them, q widgets per box, and sells them at a price of z dollars per box. What is the amount of profit, in dollars, that she makes on the sale (profit = sales revenue − cost)?


A. 100qz − xy

B. xz/q - xy/100

C. qz - xy/100

D. 100z/q - xy

E. xz/q - xy

CP = xy/100 Dollars
SP = xz/q

So, P = xz/q - xy/100
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(Step 1) Pay attention to the Units - Convert the Cost in Cents to --> Cost in $Dollars

Cost = y Cents per 1 Widget

Conversion Factor: 100 cents = $1 Dollar

[(y cents)] * [($1 Dollar / 100 Cents] = (y/100) Dollars per 1 Widget



(Step 2) Calculate Total Cost

Buys X = quantity of widgets

Cost per widget in $ = (y/100) per 1 Widget

Total Cost = (X) * (Y/100) = (XY) / (100)


(Step 3) Calculate Total Revenue/Sales

He sells the widgets by the Box-load

There are Q widgets in Each 1 Box

Total No. of Boxes = (Total No. of Widgets) / (No. of Widgets per 1 Box)

Total No. of Boxes = (X) / (Q)

and


He Sells each 1 Box for ----> Z dollars per 1 Box


Total Sales = (price per box) * (No. of Boxes) = (Z) * (X/Q) = (ZX) / (Q)


(Last Step) Profit = Revenue - Total Cost

Profit in Dollars = (ZX)/(Q) - (XY)/(100)


Correct Answer -B-

xz/q - xy/100
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Bunuel
Carol buys x widgets at a cost of y cents per widget. She packages them, q widgets per box, and sells them at a price of z dollars per box. What is the amount of profit, in dollars, that she makes on the sale (profit = sales revenue − cost)?


A. 100qz − xy

B. xz/q - xy/100

C. qz - xy/100

D. 100z/q - xy

E. xz/q - xy

The total cost of the widgets = xy cents or xy/100 dollars

Total packages made =x/q, The selling price of the packages =xz/q

Profit=xz/q-xy/100

The answer is B
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