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13 Mar 2019, 01:31
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (00:54) correct
16%
(00:57)
wrong
based on 56
sessions
History
Date
Time
Result
Not Attempted Yet
△ABC above is an isosceles triangle in which AB = AC. What is the area of △ABC?
A. 30
B. 24
C. 20
D. 15
E. 12
Attachment:
trid22 (1).png [ 8.33 KiB | Viewed 2803 times ]
13 Mar 2019, 01:40
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Using the formula:
{b(4a^2-b^2)^1/2}/4 = 12
B is the base or unequal side and a is the length of equal sides
Posted from my mobile device
{b(4a^2-b^2)^1/2}/4 = 12
B is the base or unequal side and a is the length of equal sides
Posted from my mobile device
Archit3110
Major Poster
13 Mar 2019, 03:38
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Bunuel
drop a perpendicular from A to BC D ; BD=DC= 3
so triangle ABD ; AD= 4 and area = 4*3*.5 = 6 and for complete triangel area = 12
IMO E
