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Consider another line m parallel to line k and l,passing through angle b,dividing the angle into angle X and angle a-x.
Now,between angle m and l,angle b+30=angle X
Thus,b+30=X

Between angle k and m,angle b=angle a-x

Thus,angle a=X+a-x= b+30+b=2b+30

Given angle a is acute.
Thus,2b+30<90
b<30.
Hence b.

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Consider another line m parallel to line k and l,passing through angle b,dividing the angle into angle X and angle a-x.
Now,between angle m and l,angle b+30=angle X
Thus,b+30=X

Between angle k and m,angle b=angle a-x

Thus,angle a=X+a-x= b+30+b=2b+30

Given angle a is obtuse.
Thus,2b+30<90
b<30.
Hence b.

Press Kudos if u liked my solution

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Angle a is acute not obtuse
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Sorry for the typing mistake.
But I hope,u must have got the clear intent from the solution

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if b+30 is alternate angle and by sum of all angles in a triangle is 180 logic.

[m]B+30 + B + 180 - a = 180[/m]

which is [m]B = [fraction](a-30)/2[/fraction][/m]


When a is acute angle, B will always be equal and below 30 degrees.


Anything wrong in this?
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Nothing wrong in this solution.
The only mistake is in the last line,B=(a-30)/2.
For any value of a between 0-89,b will be less than 30 degree.

Ex. When a=89,b=29.5
When a=30,b=0

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