Compute the sum of all the roots of (2x + 3)(x - 4) + (2x + 3)(x - 6)

Question

Compute the sum of all the roots of (2x + 3)(x - 4) + (2x + 3)(x - 6) = 0

(A) 7/2
(B) 4
(C) 5
(D) 7
(E) 13

Archit3110 · Answer

2x+3 * ( x-4+x-6)=0
2x+3 * (2x-10)=0
so
x=-3/2 and 5
so sum
-3/2+5 ; 7/2
IMO A

lucajava · Answer

(2x+3)  = 0 
 (2x + 3)  = 0 
Solutions:  x = {-\frac{3}{2}, 5} 
Sum:  \frac{10 - 3}{2} = \frac{7}{2}

amarprajapati92 · Answer

2x+3 ( x-4+x-6)=0
2x+3(2x-10)=0
so 2x-10=0, x=5
and 2x+3=0 x= - 3/2
5-3/2= 7/2 Ans

fmcgee1 · Answer

Why can't I do this:

(2x + 3)(x - 4) + (2x + 3)(x - 6)

x = -3/2, 4, -3/2, 6

Sum of -3/2 + -3/2 + 6 + 4 = 7

gmatpro15 · Answer

2x+3 * ( x-4+x-6)=0
2x+3 * (2x-10)=0
so
x=-3/2 and 5
so sum
-3/2+5 ; 7/2

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