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19 Mar 2019, 00:12
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
60% (02:15) correct
40%
(02:21)
wrong
based on 220
sessions
History
Date
Time
Result
Not Attempted Yet
Using the letters A, M, O, S, and U, we can form five-letter "words". If these "words" are arranged in alphabetical order, then the "word" USAMO occupies position
(A) 112
(B) 113
(C) 114
(D) 115
(E) 116
(A) 112
(B) 113
(C) 114
(D) 115
(E) 116
19 Mar 2019, 00:32
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Hi I will try to answer this,
Correct me if I'm wrong
5! = 120 rankings
arrange alphabetically
A**** = 1-24
M**** = 25-48
O**** = 49-72
S**** = 73-96
U**** = 97-120
Range 97-120
4!/4 = 6
The ranking as follows
UA*** = 97-102
UM*** = 103-108
UO*** = 109-114
US*** = 115-120
and since AMO follows the alphabetical order, it should be the first list on the US*** word list
USAMO should be Number 115
Answer D
Correct me if I'm wrong
5! = 120 rankings
arrange alphabetically
A**** = 1-24
M**** = 25-48
O**** = 49-72
S**** = 73-96
U**** = 97-120
Range 97-120
4!/4 = 6
The ranking as follows
UA*** = 97-102
UM*** = 103-108
UO*** = 109-114
US*** = 115-120
and since AMO follows the alphabetical order, it should be the first list on the US*** word list
USAMO should be Number 115
Answer D
Archit3110
19 Mar 2019, 04:29
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Bunuel
total ways to arrange AMOSU = 5!= 120 WAYS
also for each starting alphabet we have total 120/5 = 24 ways each or say 4 position each for every string of letter ...
so until letter S we would have occupied 96 positions
for rest 24 positions ; from 97-114 = 18 would be occupied in series until we reach US..
so US series will start from 115 position
IMO D
