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Bunuel
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IMO A.

area of semicircle = (π 4^2)/2
= 16π/2=8π

area of inscribed circle = π 2^2 = 4π

aonthe shaded area = 8π-4π =4π

which is half of semicircle

so in fraction it is 1/2

IMO A

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area of semicircle ; 8 pi and of circle = 4pi
so ratio
4pi/8pi = 1/2
IMO A


Bunuel

A circle of radius 2 is inscribed in a semicircle, as shown. The area inside the semicircle but outside the circle is shaded. What fraction of the semicircle's area is shaded?

(A) 1/2

(B) \(\frac{\pi}{6}\)

(C) \(\frac{2}{\pi}\)

(D) 2/3

(E) \(\frac{3}{\pi}\)


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