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Abhijeet007
Joined: 20 Jan 2018
Last visit: 04 Jun 2022
Posts: 5
Given Kudos: 420
Location: India
Concentration: Operations, International Business
Schools: Amsterdam MBA"20 HSG '20 Erasmus '20
GPA: 4
WE:Supply Chain Management (Transportation)
01 Apr 2019, 05:43
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
60% (02:21) correct
40%
(02:21)
wrong
based on 164
sessions
History
Date
Time
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Not Attempted Yet
Sam has 8 trousers and 12 shirts. 2 particular trousers can never be worn with any one of 3 particular shirts, and 2 other particular trousers must be worn with any one of 4 other particular shirts. In how many ways can Sam match up a trouser with a shirt?
(A) 94
(B) 88
(C) 66
(D) 82
(E) 74
Source:- EduShastra Class Sheet.
(A) 94
(B) 88
(C) 66
(D) 82
(E) 74
Source:- EduShastra Class Sheet.
01 Apr 2019, 07:37
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Bookmarks
\(2*9 = 18\), where 9 = 12 shirts - 3 particular shirts that can never be worn
\(2*4 = 8\)
\(4*12 = 48\), trousers without dress restrictions.
Sum all cases: \(74\). Hence, E.
\(2*4 = 8\)
\(4*12 = 48\), trousers without dress restrictions.
Sum all cases: \(74\). Hence, E.
02 Apr 2019, 04:15
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As two trousers can't be worn by 3 particular shirts, hence they can be worn by rest 9 shirts. Combination possible= 2*9
2 trousers must be worn with 4 particular shirts, combinations possible= 2*4
Rest 4 trouser can be worn with any of the 12 shirts, combination possible=4*12
Total number of combinations=74
2 trousers must be worn with 4 particular shirts, combinations possible= 2*4
Rest 4 trouser can be worn with any of the 12 shirts, combination possible=4*12
Total number of combinations=74
