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Bunuel
If \(a = 3 + b\), which of the following is true?

I. \(a > b + 2.5\)
II. \(a < b + 2.5\)
III. \(a > 2 + b\)

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I and III only

take b=1 so a= 4
IMO option 1 and option 3 are correct
IMO E
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Bunuel
If \(a = 3 + b\), which of the following is true?

I. \(a > b + 2.5\)
II. \(a < b + 2.5\)
III. \(a > 2 + b\)

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I and III only

We can let b = 2, and thus a = 5.

Let’s now analyze each Roman numeral:

I. a > b + 2.5

Is 5 > 2 + 2.5 ? YES

II. a < b + 2.5

Is 5 < 2 + 2.5 ? NO

III. a > 2 + b

Is 5 > 2 + 2 ? YES

Alternate Solution:

Since a = 3 + b, we can substitute a by (3 + b) in the inequalities.

Let’s now analyze each Roman numeral with the above-mentioned substitution:

I. a > b + 2.5

3 + b > b + 2.5 ?

3 > 2.5 → True

II. a < b + 2.5

3 + b < b + 2.5 ?

3 < 2.5 → False

III. a > 2 + b

3 + b > b + 2 ?

3 > 2 → True

Answer: E
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a = 3 + b => b = a -3

1. a > 2.5 + b => a > 2.5 + a - 3 = > a > a - 0 .5 => 0 > -0.5
True

2. a < 2.5 => 0 < 0.5
False

3. a > 2 + b => 0 > -1
True

A. E

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