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Updated on: 22 Jul 2019, 06:29
Originally posted by Bunuel on 02 Apr 2019, 23:31.
Last edited by Sajjad1994 on 22 Jul 2019, 06:29, edited 1 time in total.
Last edited by Sajjad1994 on 22 Jul 2019, 06:29, edited 1 time in total.
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Difficulty:
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68% (02:08) correct
32%
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In the figure, lines \(\ell 1\), \(\ ell 2\), and \(\ell 3\) are parallel to one another. Line-segments AC and DF cut the three lines. If AB = 3, BC = 4, and DE = 5, then which one of the following equals DF ?
(A) \(\frac{3}{30}\)
(B) \(\frac{15}{7}\)
(C) \(\frac{20}{3}\)
(D) \(6\)
(E) \(\frac{35}{3}\)
Source: Nova GMAT
Difficulty Level: 600
Difficulty Level: 600
Attachment:
#GREpracticequestion In the figure, lines l1, l2, and l3 are parallel to one another.jpg [ 22.41 KiB | Viewed 4624 times ]
aniket16c
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03 Apr 2019, 21:45
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Theorem: 3 parallel lines divide two intercepts in equal ratio.
Thus: AB/BC = DE/EF
EF = 20/3
DF = 20/3+5=35/3
Thus: AB/BC = DE/EF
EF = 20/3
DF = 20/3+5=35/3
03 Apr 2019, 21:59
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Theorem: 3 parallel lines divide two intercepts in equal ratio.
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