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\(x + y = 7\)
\(x^2 + y^2 = 25\)

\(7\) as sum of two numbers is given by: 4+3; 6+1; 5+2 ...

If the second equation is verified, pick them; otherwise, reject them.

\(4^2 + 3^2 = 16\)? Yes. Pick them.

\(4^3 + 3^3 = 64 + 27 = 91\). Correct answer: E.
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Bunuel
If \(x + y = 7\) and \(x^2 + y^2 = 25\), then which one of the following equals the value of \(x^3 + y^3\) ?

(A) 7

(B) 25

(C) 35

(D) 65

(E) 91

----ASIDE---------------
We COULD use some algebra to solve the question.
First rewrite the first equation as x = 7 - y
Then take second equation and replace x with 7 - y to get: (7 - y)² + y² = 25
When we eventually solve the system, we get two possible solutions:
Solution #1: x = 3 and y = 4
Solution #2: x = 4 and y = 3
-----------------------------

Solving the question is the above way takes time. So, before resorting to algebra, we might first see if we can solve the question through inspection.
If we do so, we might quickly realize that one value must be 3 and the other must be 4.

So, x³ + y³ = 3³ + 4³
= 27 + 64
= 91

Answer: E

Cheers,
Brent
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Bunuel
If \(x + y = 7\) and \(x^2 + y^2 = 25\), then which one of the following equals the value of \(x^3 + y^3\) ?

(A) 7

(B) 25

(C) 35

(D) 65

(E) 91

Since x + y = 7, (x + y)^2 = 7^2 → x^2 + 2xy + y^2 = 49. Since x^2 + y^2 = 25, we have 25 + 2xy = 49 → 2xy = 24 → xy = 12.

Recall that x^3 + y^3 factored as (x + y)(x^2 - xy + y^2), so we have:

x^3 + y^3 = (7)(25 - 12) = 7(13) = 91

Answer: E
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