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sanyamjain2408
There are 4 possibilities to get sum of positive numbers as 5:
(1,4) (4,1)
(2,3) (3,2)
And:-(c) 1/4

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sanyamjain2408
any reason why did not consider 0 pair?
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Archit3110
Because 0 is a not a positive number.

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Archit3110
Because 0 is a not a positive number.

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yes x>0 in this case got it thanks
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IMO C

x can take values 1 to 4

so probab of getting x = 1

is 1/4

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Bunuel
If x and y are two positive integers and x + y = 5, then what is the probability that x equals 1?

(A) 1/2
(B) 1/3
(C) 1/4
(D) 1/5
(E) 1/6

The options for (x,y) are:

(1,4)

(4,1)

(3,2)

(2,3)

So the probability that x is 1 is 1/4.

Answer: C
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Theory: Probability of Occurrence of and event P(E) is given by

P(E) = Number of Favorable Outcomes / Total Number of Outcomes


Given that x and y are two positive integers and x + y = 5 and we need to find the probability that x equals 1

Let's start by writing all the possible outcomes for x+y = 5, given that both x and y are positive integers. Possible outcomes are

x = 1, y = 4
x = 2, y = 3
x = 3, y = 2
x = 4, y = 1

So, Total Number of Outcomes = 4
Number of Favorable outcomes in which x = 1 is 1 (x = 1, y = 4)

=> Probability (x=1) = (Favorable outcomes in which x = 1) / Total Number of Outcomes = \(\frac{1}{4}\)

So, Answer will be C.
Hope it helps!
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