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Sub 505 (Easy)|   Geometry|               
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third side rule simple
sum <7 and >1
IMO B

Bunuel

Which of the following gives all possible values of x in the figure above?

A. 1 < x < 4
B. 1 < x < 7
C. 3 < x < 5
D. 4 < x < 7
E. 5 < x < 12


PS05602.01
Quantitative Review 2020 NEW QUESTION


Attachment:
2019-04-26_1739.png
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Solution


Given
In this question, we are given
    • The diagram of a triangle PQR, with side lengths PQ = 3, QR = 4, and PR = x

To Find
We need to determine
    • Among the given choices, which range defines all possible values of x.

Approach & Working
We know that, for any given triangle, sum of any two sides is always greater than the third side.

Therefore, we can say
    • 3 + 4 > x
    Or, x < 7

Similarly, x + 4 > 3
    Or, x > 1

Combining the two results, we can conclude 1 < x < 7.

Hence, the correct answer is option B.

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Bunuel

Which of the following gives all possible values of x in the figure above?

A. 1 < x < 4
B. 1 < x < 7
C. 3 < x < 5
D. 4 < x < 7
E. 5 < x < 12


PS05602.01
Quantitative Review 2020 NEW QUESTION


Attachment:
2019-04-26_1739.png


In any triangle, the length of the third side must be more than the difference of the other sides and less than the sum of those two sides. Therefore, we have:

4 - 3 < x < 4 + 3

1 < x < 7

Answer: B
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Bunuel

Which of the following gives all possible values of x in the figure above?

A. 1 < x < 4
B. 1 < x < 7
C. 3 < x < 5
D. 4 < x < 7
E. 5 < x < 12


PS05602.01
Quantitative Review 2020 NEW QUESTION


Attachment:
2019-04-26_1739.png

A property of a triangle is: The length of the third side must be greater than the difference of the other two sides and less than the sum of those two sides.

So, \(4 - 3 < x < 4 + 3\) \(= 1 < x < 7\)

The Answer is B
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Theory: Each Side of the Triangle is between the | Difference of the other two sides | and Sum of the other two sides

=> |PQ - QR| < PR < PQ + QR
=> |3 - 4| < x < 3 + 4
=> |-1| < x < 7
=> 1 < x < 7

So, Answer will be B
Hope it helps!
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