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Runners X and Y started an 18-mile race at the same time. Runner X completed the course in 6 hours, and Runner Y finished 2 hours earlier. Runner Y ran an average of how many miles per hour faster than Runner X?

A. 1

B. 1\(\frac{1}{2}\)

C. 2\(\frac{1}{4}\)

D. 3

E. 4\(\frac{1}{2}\)

Solution:

The average speed of runner X is 18/6 = 3 mph, and the average speed of runner Y is 18/4 = 4.5 mph. Therefore, the average speed of runner Y is 4.5 - 3 = 1.5 mph faster than the average speed of runner X.

Answer: B
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