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01 May 2019, 11:59
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
31% (02:13) correct
69%
(02:19)
wrong
based on 95
sessions
History
Date
Time
Result
Not Attempted Yet
'P' is the product of 10 consecutive two-digit natural numbers. If \(2^a\) is one of the factors of P, then the maximum possible value of a is
1. 11
2. 10
3. 12
4. 14
5. 13
1. 11
2. 10
3. 12
4. 14
5. 13
01 May 2019, 12:36
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nick1816
\(10! = 10*11*12*13*14*15*16*17*18*19*20\)
Count the number of 2's in it, Answer will be 13, Answer must be (E) 13
correct answer but wrong approach
1. You consider 11 natural numbers.
2. You missed the trick!! You must consider the highest two-digit number which you can write in the form of (\(2^x\))
In our case that is 64 which is equal to \(2^6\). ( as \(2^7\) is a 3 digit number so you can't consider it.
Now any 10 consecutive numbers which include 64 and another multiple of 8 will give you the right answer
For example 64*65*66*67*68*69*70*71*72*73
6 + 1 + 2 + 1 + 3 =13
1. You consider 11 natural numbers.
2. You missed the trick!! You must consider the highest two-digit number which you can write in the form of (\(2^x\))
In our case that is 64 which is equal to \(2^6\). ( as \(2^7\) is a 3 digit number so you can't consider it.
Now any 10 consecutive numbers which include 64 and another multiple of 8 will give you the right answer
For example 64*65*66*67*68*69*70*71*72*73
6 + 1 + 2 + 1 + 3 =13
Abhishek009
