As you start off solving this question, you may feel that the data is insufficient and that the question is a difficult one on Geometry. However, that is not the case. The concept, basis which you can solve this question is as described below:
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Let’s consider a rectangle of length ‘l’ and breadth ‘b’.
On one of the longer sides, say CD, let’s mark a point, say E to which the endpoints of the other length, i.e. A and B are joined. In such a case, the triangle formed with the length AB as the base , will always have an area that is equal to half the area of the rectangle.
Also, the other two smaller triangles i.e. \(\triangle BCE\) and \(\triangle ADE\), will contribute the other half of the area of the rectangle (this is not to say that the area of the two smaller triangles will always be one-quarter of the rectangle).
Once you know this concept, it becomes very easy for you to figure out that this is the concept on which you are being tested in this question.
In the diagram that we have, \(\triangle ACE\) is clearly a triangle which has been drawn keeping AE, the length of the rectangle, as the base. Hence, the area of \(\triangle ACE\) should be half of the area of the rectangle ABDE.
Therefore, the area of \(\triangle ACE\) is 9 square units and the correct answer option is A.
If you knew this concept beforehand, you will barely need half a minute to solve this question and mark the right answer. If this concept was a little obscure till now, we hope that we have provided clarity on this.
Hope this helps!