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Given:

\(x^3\) = n and the units digit of n is a prime number.

Prime numbers have exatcly two factors: 1 and the number itself. Examples of prime numbers are 2 , 3 , 5 , 7 . 11 and so on.

Now, let us check for the given cases

Case I

if x = 1

then \(x^3\) = n = 1 , BUT 1 is not a prime number as 1 has only one factor. Therefore the unit digits of n is not a prime number.

Case I is not possible

Case II

if x = 8

\(x^3\) = n = \(8^3\) = 512 . The units digit of n (2) is a prime number.

Case II is possible

Case III

if x = 9

\(x^3\) = n = \(9^3\) = 729. The units digit of n (9) is not a prime number as it has 3 factors : 1 , 3 , 9

Case III is not possible

So only case II is possible.

The correct answer is B
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