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02 Jun 2019, 22:08
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70% (02:30) correct
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The average age of three friends A, B and C is 7 years. Five years later, the average age of A and C will be 1½ years more than B’s age then. How old will B be 10 years hence (in years)
A. 10
B. 12
C. 14
D. 16
E. 18
A. 10
B. 12
C. 14
D. 16
E. 18
03 Jun 2019, 04:20
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A+B+C = 21 years.
5 years later ((A+5)+(b+5))/2 = 1.5+B+5 ; simplifying A+C+10=13+2B ; Adding B on both sides A+B+C = 3+3B; 21 = 3+3B; B= 6. Ten years later b=16
5 years later ((A+5)+(b+5))/2 = 1.5+B+5 ; simplifying A+C+10=13+2B ; Adding B on both sides A+B+C = 3+3B; 21 = 3+3B; B= 6. Ten years later b=16
03 Jun 2019, 18:24
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(A+B+C)/3 = 7
A+B+C = 21
5 Years Later,
(A+C)/2 +5 = 3/2 + B + 5
Since A + B + C = 21 , we know that A+C = 21-B
Replace in above equation,
(21-B)/2 = 3/2 + B
B = 6
10 Years Later,
B =16
A+B+C = 21
5 Years Later,
(A+C)/2 +5 = 3/2 + B + 5
Since A + B + C = 21 , we know that A+C = 21-B
Replace in above equation,
(21-B)/2 = 3/2 + B
B = 6
10 Years Later,
B =16
