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Bunuel
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In Clarice’s class, each test weights her overall grade average three 03 Jun 2019, 01:04
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B
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71% (01:52) correct 29% (02:22) wrong based on 232 sessions

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In Clarice’s class, each test weights her overall grade average three times as much as each quiz does. If Clarice scored 88 and 94 on two quizzes, respectively, and she scored 90 on the only test, what is her current overall grade average?

(A) 90.5

(B) 90.4

(C) 90.3

(D) 90.2

(E) 89
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B
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In Clarice’s class, each test weights her overall grade average three 03 Jun 2019, 01:13
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Weighted Mean=(88*1)+(94*1)+(90*3)/(1+1+3)
=452/5
=90.4
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In Clarice’s class, each test weights her overall grade average three 03 Jun 2019, 09:30
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Bunuel
In Clarice’s class, each test weights her overall grade average three times as much as each quiz does. If Clarice scored 88 and 94 on two quizzes, respectively, and she scored 90 on the only test, what is her current overall grade average?

(A) 90.5

(B) 90.4

(C) 90.3

(D) 90.2

(E) 89
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confusing question what I could understand
each test weights her overall grade average three times as much as each quiz does
88*1+94*1+3*90 = 452
avg ; 452/5 ; 90.4
IMO B
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In Clarice’s class, each test weights her overall grade average three 06 Jun 2019, 17:53
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Bunuel
In Clarice’s class, each test weights her overall grade average three times as much as each quiz does. If Clarice scored 88 and 94 on two quizzes, respectively, and she scored 90 on the only test, what is her current overall grade average?

(A) 90.5

(B) 90.4

(C) 90.3

(D) 90.2

(E) 89
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We can create the equation:

[94 + 88 + 3(90)]/(1 + 1 + 3)

(182 + 270)/5 = 452/5 = 90.4

Answer: B
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In Clarice’s class, each test weights her overall grade average three 30 Oct 2021, 09:30
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each test weights her overall grade average three times as much as each quiz does.

Total weight = 3*test score + Sum of Quiz score = 3*90 + 94 +88 = 452.

Avg. weight = 452/(3+1+1) = 90.4.

So, I think B. :)
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In Clarice’s class, each test weights her overall grade average three 10 Dec 2024, 07:12
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