Find the number of integers divisible by 3 in the interval from 10 to

Question

Find the number of integers divisible by 3 in the interval from 10 to 200 inclusive.

(A) 61
(B) 62
(C) 63
(D) 64
(E) 65

Lampard42 · Answer

200/3 = 66.66 i.e 66 integers are divisible from 1 to 200. Reduce 3 which are between 1 to 10. So IMO Option C 63

Archit3110 · Answer

first no 12 and last 198 ; 66 and 4
66-4+1 ;63
IMO C

CareerGeek · Answer

Multiples of 3 from 10 to 200 are
12, 15, 18, . . . . . 198

The above is AP series. To find number of terms, use last term
198 = 12 + (n - 1)3
—>186 = (n - 1)3
—> n - 1 = 62
—> n = 63

IMO Option C.

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kitipriyanka · Answer

b/w 10 and 200:
first no divisible by 3 is 12=3*4
last no divisible by 3 is 198=3*66

Therefore,total numbers divisible by 3 b/w 10 and 200 = 66-4+1=63

Hence C

Starfruit · Answer

Between 10 and 200: 
- the first number divisible by 3 is 12
- the last number divisible by 3 is 198

The total number divisible by 3 is: (198-12)/3+1 = 63

IMO option C

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ScottTargetTestPrep · Answer

In the given interval, the smallest multiple of 3 is 12, and the greatest multiple of 3 is 198. Thus, the number of multiples of 3 is:

(198 - 12)/3 + 1 = 63

Answer: C

Abhishek009 · Answer

No of integers divisible between  1 - 200 = \frac{200}{3} = 66 
No of integers divisible between  1 - 10 = \frac{200}{3} = 3

Thus, no of integers divisible by 3 in the interval from 10 - 200 inclusive  = 66 - 3 = 63 , Answer must be (C)

bumpbot · Answer

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Find the number of integers divisible by 3 in the interval from 10 to

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