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Bunuel
On a rectangular plot of land 60 meters wide and 80 meters long, the owner wants to install a road 5 meters wide around the perimeter of the entire property, entirely contained within the property. What will be the surface area of that road?


(A) 675
(B) 1,300
(C) 1,400
(D) 1,500
(E) 1,675

total area = 80*60 ; 4800
and of road inside will reduce the l to 70 and w to 50; 3500
4800-3500 = 1300 area of road
IMO B
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hi ,

Why is the length 80-10 and width 60- 10 rather than 80-5 and 60-5 ? I am missing something here

Thanks



Archit3110
Bunuel
On a rectangular plot of land 60 meters wide and 80 meters long, the owner wants to install a road 5 meters wide around the perimeter of the entire property, entirely contained within the property. What will be the surface area of that road?


(A) 675
(B) 1,300
(C) 1,400
(D) 1,500
(E) 1,675

total area = 80*60 ; 4800
and of road inside will reduce the l to 70 and w to 50; 3500
4800-3500 = 1300 area of road
IMO B
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Rose2012
hi ,

Why is the length 80-10 and width 60- 10 rather than 80-5 and 60-5 ? I am missing something here

Thanks



Archit3110
Bunuel
On a rectangular plot of land 60 meters wide and 80 meters long, the owner wants to install a road 5 meters wide around the perimeter of the entire property, entirely contained within the property. What will be the surface area of that road?


(A) 675
(B) 1,300
(C) 1,400
(D) 1,500
(E) 1,675

total area = 80*60 ; 4800
and of road inside will reduce the l to 70 and w to 50; 3500
4800-3500 = 1300 area of road
IMO B

Rose2012 this question is similar to a picture frame question. The point is when the length on 2 sides get shortened by 5 the width gets shortened by 10. Similarly for length. So we do 2*reduction.

Hope this helps! I have attached a pic to understand it better

Posted from my mobile device
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7FB6B90E-B52F-4D09-9F50-6B953B7C3A86.jpeg
7FB6B90E-B52F-4D09-9F50-6B953B7C3A86.jpeg [ 2.28 MiB | Viewed 5355 times ]

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