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prashanths
If the nth term of the series 9,7,5,3 … is same as the nth term of the series 15, 12 , 9, 6 … find n.

A) 10
B) 7
C) 12
D) 8
E) 11

Both the given series are in AP
—> nth term of 1st series, \(T_n\)= 9 + (n - 1)(-2) = 11 - 2n
and nth term of 2nd series, \(T_n\) = 15 +!(n - 1)(-3) = 18 - 3n

nth term of the series 9,7,5,3 … is same as the nth term of the series 15, 12 , 9, 6 …
—> 11 - 2n = 18 - 3n
—> 3n - 2n = 18 - 11
—> n = 7

IMO Option B

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