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01 Jul 2019, 01:27
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
61% (03:19) correct
39%
(02:48)
wrong
based on 38
sessions
History
Date
Time
Result
Not Attempted Yet
A circle C in XY coordinate has equation x^2 + y^2 = 4 and a line L having equation x = 1 cuts the circle into 2 parts. What is the area of smaller portion cut inside the circle C?
A. \(\frac{4\pi}{3} - \sqrt{2}\)
B. \(\frac{2\pi}{3} - \sqrt{3}\)
C. \(\frac{4\pi}{3} - \sqrt{3}\)
D. \(\frac{2\pi}{3} - \sqrt{6}\)
E. \(\pi\)
A. \(\frac{4\pi}{3} - \sqrt{2}\)
B. \(\frac{2\pi}{3} - \sqrt{3}\)
C. \(\frac{4\pi}{3} - \sqrt{3}\)
D. \(\frac{2\pi}{3} - \sqrt{6}\)
E. \(\pi\)
WiziusCareers1
Joined: 27 Apr 2009
Last visit: 09 Jun 2026
Posts: 180
Given Kudos: 35
Status:Not Applying
Location: India
Schools: HBS '14 (A)
GMAT 1: 730 Q51 V36
01 Jul 2019, 04:08
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The line cuts the circle at (1, √3) and (1, -√3).
=> The length of the chord is 2√3.
=> The area of the sector is (120)/(360) * pi * (2) * (2) = 4pi/3
Area of the triangle is 1/2 * (2√3) * 1 =√3
The area of the smaller part of the circle = (4pi/3) - √3
Hence, the answer is (C).The line cuts the circle at (1, √3) and (1, -√3).
=> The length of the chord is 2√3.
=> The area of the sector is (120)/(360) * pi * (2) * (2) = 4pi/3
Area of the triangle is 1/2 * (2√3) * 1 =√3
The area of the smaller part of the circle = (4pi/3) - √3
Hence, the answer is (C).
=> The length of the chord is 2√3.
=> The area of the sector is (120)/(360) * pi * (2) * (2) = 4pi/3
Area of the triangle is 1/2 * (2√3) * 1 =√3
The area of the smaller part of the circle = (4pi/3) - √3
Hence, the answer is (C).The line cuts the circle at (1, √3) and (1, -√3).
=> The length of the chord is 2√3.
=> The area of the sector is (120)/(360) * pi * (2) * (2) = 4pi/3
Area of the triangle is 1/2 * (2√3) * 1 =√3
The area of the smaller part of the circle = (4pi/3) - √3
Hence, the answer is (C).
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13 Sep 2023, 06:19
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