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03 Jul 2019, 03:54
Kudos
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
73% (02:46) correct
27%
(02:58)
wrong
based on 201
sessions
History
Date
Time
Result
Not Attempted Yet
Jhon bought an ordinary mobile and a cover for $ 2000. Prince bought a smart phone and the same cover for $ 2000 more than what Jhon had paid. The price of the cover was one tenth of the combined cost of 2 mobiles. what is the cost of the ordinary mobile?
A) $1000
B) $1200
C) $1500
D) $1600
E)$1800
A) $1000
B) $1200
C) $1500
D) $1600
E)$1800
03 Jul 2019, 06:07
Kudos
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KSBGC
Let M = cost of ordinary mobile
Let C = cost of the cover
Let S = cost of smart mobile
Jhon bought an ordinary mobile and a cover for $ 2000
We get: M + C = 2000
Prince bought a smart phone and the same cover for $ 2000 more than what Jhon had paid.
We get: S + C = 4000
The price of the cover was one tenth of the combined cost of 2 mobiles. what is the cost of the ordinary mobile?
We get: C = 1/10(M + S)
Multiply both sides by 10 to get: 10C = M + S
Lots of options from here. Here's one approach:
Take:
M + C = 2000
S + C = 4000
ADD them to get: M + S + 2C = 6000
Replace M + S with 10C to get: 10C + 2C = 6000
Simplify: 12C = 6000
Solve: C = 6000/12 = 500
We already know that M + C = 2000
Since C = 500, we can see that M = 1500
Answer: C
Cheers,
Brent
General Discussion
WiziusCareers1
Joined: 27 Apr 2009
Last visit: 24 Apr 2026
Posts: 178
Given Kudos: 35
Status:Not Applying
Location: India
Schools: HBS '14 (A)
GMAT 1: 730 Q51 V36
03 Jul 2019, 04:33
Kudos
Bookmarks
Let the cost of the ordinary mobile be m, cost of the cover be c and the cost of the smart mobile be s.
=> m + c = 2000......(i)
and s + c = 4000......(ii)
Also, c = (s + m)/10......(iii)
Putting (iii) in (i) and (ii), we get
11m + s = 20,000
m + 11s = 40,000
Adding the two equations above, we get 12(m + s) = 60,000
=> m + s = 5,000
=> c = 5,000/10 = 500
If c = 500, then m = 1500.
The answer is (C).
=> m + c = 2000......(i)
and s + c = 4000......(ii)
Also, c = (s + m)/10......(iii)
Putting (iii) in (i) and (ii), we get
11m + s = 20,000
m + 11s = 40,000
Adding the two equations above, we get 12(m + s) = 60,000
=> m + s = 5,000
=> c = 5,000/10 = 500
If c = 500, then m = 1500.
The answer is (C).
