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21 Aug 2019, 01:46
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (01:32) correct
24%
(01:38)
wrong
based on 87
sessions
History
Date
Time
Result
Not Attempted Yet
John is now 10 years older than Janice. If 10 years ago John was twice as old as Janice, how old will John be in 5 years?
A. 10
B. 18
C. 23
D. 25
E. 35
A. 10
B. 18
C. 23
D. 25
E. 35
21 Aug 2019, 01:53
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X=Y+10
X-10=2(Y-10), X=2Y-10
2Y-10=Y+10 ,Y=20
X=30
So, in 5 years John will be 35
Option E
Posted from my mobile device
X-10=2(Y-10), X=2Y-10
2Y-10=Y+10 ,Y=20
X=30
So, in 5 years John will be 35
Option E
Posted from my mobile device
21 Aug 2019, 02:18
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Explanation:
Assume present age:
John = a
Janice = b
Now equation is,
a = b+10 ..(1)
a-10 = 2(b-10) ..(2)
Solving 1 & 2, we get b=20
So a = 30
To find a+5 = 35 answer.
IMO, option E
Posted from my mobile device
Assume present age:
John = a
Janice = b
Now equation is,
a = b+10 ..(1)
a-10 = 2(b-10) ..(2)
Solving 1 & 2, we get b=20
So a = 30
To find a+5 = 35 answer.
IMO, option E
Posted from my mobile device
