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When the integer Y is divided by 11, the remainder is 3. Which of the 09 Sep 2019, 23:42
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When the integer Y is divided by 11, the remainder is 3. Which of the following can't be a multiple of (Y+1)?

A. 2Y + 2.
B. 1.5Y + 9.
C. 2.5Y – 5.
D. 3Y + 3.
E. 3Y – 5.
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E
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When the integer Y is divided by 11, the remainder is 3. Which of the 10 Sep 2019, 02:16
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Bunuel
When the integer Y is divided by 11, the remainder is 3. Which of the following can't be a multiple of (Y+1)?

A. 2Y + 2.
B. 1.5Y + 9.
C. 2.5Y – 5.
D. 3Y + 3.
E. 3Y – 5.
Show more

let y =14
option E ; is prime no
IMO E
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When the integer Y is divided by 11, the remainder is 3. Which of the 21 Aug 2020, 10:16
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Archit3110
Bunuel
When the integer Y is divided by 11, the remainder is 3. Which of the following can't be a multiple of (Y+1)?

A. 2Y + 2.
B. 1.5Y + 9.
C. 2.5Y – 5.
D. 3Y + 3.
E. 3Y – 5.

let y =14
option E ; is prime no
IMO E
Show more

If Y = 3, then the remainder for \(\frac{3}{11}\) is 3 which satisfies the constraint mentioned.

In that case Option E = (3*3) - 5 = 4, which is a multiple of Y + 1

Here B or C could be the answers, as they are not multiples of 4 when Y = 3.

Just want to know if I am on the right track here. Thanks.

Arun Kumar
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When the integer Y is divided by 11, the remainder is 3. Which of the 21 Aug 2020, 10:42
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CrackVerbalGMAT
since given that y is an integer so we need to test all given options of y where we always get an integer value ( for given options) which is at y= 14 only..

though other possibilities of y are as follows which when divided by 11 gives remainder 3
y =3,14,25,36,47,58
and y+1 ; 4,15,26,37,48,59



A. 2Y + 2 ; ( check at y ,14,) yes possible
B. 1.5Y + 9. ; ( check at y = 14 (possible)
C. 2.5Y – 5.; ( y = 14, possible)
D. 3Y + 3. ; ( y =14, possible)
E. 3Y – 5 ; ( y = 3 possible but not at y = 14,)
we see that only option E is not valid for integer values >11 at y = 14 ;

CrackVerbalGMAT
Archit3110
Bunuel
When the integer Y is divided by 11, the remainder is 3. Which of the following can't be a multiple of (Y+1)?

A. 2Y + 2.
B. 1.5Y + 9.
C. 2.5Y – 5.
D. 3Y + 3.
E. 3Y – 5.

let y =14
option E ; is prime no
IMO E

If Y = 3, then the remainder for \(\frac{3}{11}\) is 3 which satisfies the constraint mentioned.

In that case Option E = (3*3) - 5 = 4, which is a multiple of Y + 1

Here B or C could be the answers, as they are not multiples of 4 when Y = 3.

Just want to know if I am on the right track here. Thanks.

Arun Kumar
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When the integer Y is divided by 11, the remainder is 3. Which of the 21 Aug 2020, 19:41
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Archit3110
CrackVerbalGMAT
since given that y is an integer so we need to test all given options of y where we always get an integer value ( for given options) which is at y= 14 only..

though other possibilities of y are as follows which when divided by 11 gives remainder 3
y =3,14,25,36,47,58
and y+1 ; 4,15,26,37,48,59



A. 2Y + 2 ; ( check at y ,14,) yes possible
B. 1.5Y + 9. ; ( check at y = 14 (possible)
C. 2.5Y – 5.; ( y = 14, possible)
D. 3Y + 3. ; ( y =14, possible)
E. 3Y – 5 ; ( y = 3 possible but not at y = 14,)
we see that only option E is not valid for integer values >11 at y = 14 ;

CrackVerbalGMAT
Archit3110
Bunuel
When the integer Y is divided by 11, the remainder is 3. Which of the following can't be a multiple of (Y+1)?

A. 2Y + 2.
B. 1.5Y + 9.
C. 2.5Y – 5.
D. 3Y + 3.
E. 3Y – 5.

let y =14
option E ; is prime no
IMO E

If Y = 3, then the remainder for \(\frac{3}{11}\) is 3 which satisfies the constraint mentioned.

In that case Option E = (3*3) - 5 = 4, which is a multiple of Y + 1

Here B or C could be the answers, as they are not multiples of 4 when Y = 3.

Just want to know if I am on the right track here. Thanks.

Arun Kumar
Show more


Hi Archit 3110. Thank you for the reply.

The question does not mention a constraint on the value of Y. Which is why the doubt arose in the first place.

The question can be construed as " which of the following can never be a factor of Y + 1".

So which option, for any value of Y cannot be a multiple of Y + 1.

Maybe the question should have mentioned this.

Thanks

Arun Kumar
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When the integer Y is divided by 11, the remainder is 3. Which of the 22 Aug 2020, 01:52
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Archit3110

since given that y is an integer so we need to test all given options of y where we always get an integer value ( for given options) which is at y= 14 only..

though other possibilities of y are as follows which when divided by 11 gives remainder 3
y =3,14,25,36,47,58
and y+1 ; 4,15,26,37,48,59



A. 2Y + 2 ; ( check at y ,14,) yes possible
B. 1.5Y + 9. ; ( check at y = 14 (possible)
C. 2.5Y – 5.; ( y = 14, possible)
D. 3Y + 3. ; ( y =14, possible)
E. 3Y – 5 ; ( y = 3 possible but not at y = 14,)
we see that only option E is not valid for integer values >11 at y = 14 ;

Show more

Hi Archit3110 , I'm sorry I have a doubt. You said that "so we need to test all given options of y where we always get an integer value ( for given options) which is at y= 14 only.." but option E is still failing for y=14 whereas it is not for y=3, and there are other options which are failing for some values of y and not for others, then how are we concluding E to be the answer? If it is because at y=14, every option fits except E, then can you please tell me how I can tell that the question is asking so? As in if I get a question like this, how can I make out that this is what they're asking?
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When the integer Y is divided by 11, the remainder is 3. Which of the 22 Aug 2020, 08:42
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Dear All

Greetings.
Y can also be equal to 3.
3/11 leaves a remainder of 3.
Y+1 is equal to 4 if I take Y=3. --- (1)

Option E states that 3Y – 5 can't be a multiple of Y.
But, if we take Y as 3, then 3Y-5=3(3)-5
9-5=4. ---(2)

Clearly, (2) is divisible by (1).
Kindly explain.
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When the integer Y is divided by 11, the remainder is 3. Which of the 03 Sep 2024, 06:04
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gasoline
Dear All

Greetings.
Y can also be equal to 3.
3/11 leaves a remainder of 3.
Y+1 is equal to 4 if I take Y=3. --- (1)

Option E states that 3Y – 5 can't be a multiple of Y.
But, if we take Y as 3, then 3Y-5=3(3)-5
9-5=4. ---(2)

Clearly, (2) is divisible by (1).
Kindly explain.
Show more

we are dealing with y+1 here

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