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chetan2u
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Positive integer N has k positive divisors, and k has x positive divisors. If k and x are odd integers greater than 2, what is the least possible value of N - k - x?

A) -2
B) 9
C) 17
D) 24
E) 36


Odd integers means all are SQUARES..
We will have to take least value of N, for that k has to be least and in turn x has to be least
k has x positive divisors, so least value of x can be 3...


3 positive divisors means perfect square of a prime number, so 3^2=9 as 3 is the smallest odd prime number

Now N has 9 prime factors..
Different values of N ..
1) 9=1*9=(8+1) or \(a^8\)...Minimum value 2^8=256
2) 9=3*3=(2+1)(2+1) or \(a^2b^2\).. Taking least value of a and b, we get \(2^23^2=36\)

Thus N-k-x=36-9-3=24

D

Hi chetan2u

I understand(green part) that x's least value is 3 since only set of factors (1,3,9) satisfies the condition though (1,2,4) also has three but it would make K even.
(is my understanding correct till this point?)

However, the red part and afterwards i didn't understand.
Why would N have 9 'prime' factors.?

Normally i understand your solutions and like the simplicity of them. But here i am stuck.
Can you help explain?
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chetan2u
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Positive integer N has k positive divisors, and k has x positive divisors. If k and x are odd integers greater than 2, what is the least possible value of N - k - x?

A) -2
B) 9
C) 17
D) 24
E) 36


Odd integers means all are SQUARES..
We will have to take least value of N, for that k has to be least and in turn x has to be least
k has x positive divisors, so least value of x can be 3...


3 positive divisors means perfect square of a prime number, so 3^2=9 as 3 is the smallest odd prime number

Now N has 9 prime factors..
Different values of N ..
1) 9=1*9=(8+1) or \(a^8\)...Minimum value 2^8=256
2) 9=3*3=(2+1)(2+1) or \(a^2b^2\).. Taking least value of a and b, we get \(2^23^2=36\)

Thus N-k-x=36-9-3=24

D

Hi chetan2u

I understand(green part) that x's least value is 3 since only set of factors (1,3,9) satisfies the condition though (1,2,4) also has three but it would make K even.
(is my understanding correct till this point?)

However, the red part and afterwards i didn't understand.
Why would N have 9 'prime' factors.?

Normally i understand your solutions and like the simplicity of them. But here i am stuck.
Can you help explain?

Yes, your understanding is pretty much correct. (x,K) has to be both odd and greater than 2, eg. (3,9).

(2,4) is out because it doesn't satistify the condition that x and K have to be odd and greater than 2.

What chetan2u actually means is that N should have 9 divisors/factors, NOT 'prime' factors. 2 cases were considered as he explained.

Hope this explanation makes you understand more easily and better.

Posted from my mobile device
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This is how I approached this question:

1. We are asked for the least value, and we know that perfect squares have odd number of factors
2. Start looking for the smallest perfect square such that k and x are \(>2\)

1. \(2^2 = 4\) [\(N=4\), \(k=3\) (1,2,4) and \(x=2\) (1,3)] - x is not greater than 2
2. \(3^2 = 9\) [\(N=9\), \(k=3\) (1,3,9) and \(x=2\) (1,3)] - x is not greater than 2
3. \(4^2 = 16\) [\(N=16\), \(k=5\) (1,2,4,8,16) and \(x=2\) (1,5)] - x is not greater than 2
4. \(5^2 = 25\) [\(N=25\), \(k=3\) (1,5,25) and \(x=2\) (1,3)] - x is not greater than 2
5. \(6^2 = 36\) [\(N=36\), \(k=9\) (1,2,3,4,6,9,12,18,36) and \(x=3\) (1,3,9)] - satisfies the condition \(k, x >2\)

Now,

\(N-k-x\)\(= 36-9-3\)\(= 24\) (Ans. D)
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