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Sub 505 (Easy)|   Arithmetic|      
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Bunuel
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(3 X 100) + (4 X 1) + (5 X 1,000) + (6 X 10) = 25 Sep 2019, 02:02
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E
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Difficulty:

5% (low)

Question Stats:

98% (00:23) correct 2% (00:12) wrong based on 51 sessions

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(3*100) + (4*1) + (5*1,000) + (6*10) =

(A) 3,456
(B) 3,564
(C) 4,635
(D) 5,346
(E) 5,364
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E
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(3 X 100) + (4 X 1) + (5 X 1,000) + (6 X 10) = 25 Sep 2019, 11:23
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becuase it is 5*100 plus 3*100, the answer must be more than 5300. Since the unit has 4*1, the unit digit should be 4. You have 5364; the correct chocie is E.
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(3 X 100) + (4 X 1) + (5 X 1,000) + (6 X 10) = 25 Sep 2019, 11:54
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Bunuel
(3*100) + (4*1) + (5*1,000) + (6*10) =

(A) 3,456
(B) 3,564
(C) 4,635
(D) 5,346
(E) 5,364
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5000+300+60+4=5364.
Option E.
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(3 X 100) + (4 X 1) + (5 X 1,000) + (6 X 10) = 27 Sep 2019, 08:44
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Bunuel
(3*100) + (4*1) + (5*1,000) + (6*10) =

(A) 3,456
(B) 3,564
(C) 4,635
(D) 5,346
(E) 5,364
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We see that the thousands digit is 5, the hundreds is 3, the tens is 6, and the ones is 4. Thus, the correct answer is 5,364.

Answer: E
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(3 X 100) + (4 X 1) + (5 X 1,000) + (6 X 10) = 29 Sep 2019, 14:26
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Solution



Approach and Working out
You can easily add the number.
• 3*100 = 300
• 4 * 1 = 4
• 5*1000= 5000
• 6*10 = 60
(3*100) + (4*1) + (5*1,000) + (6*10) = 5364

Thus, option E is the correct answer.

Correct Answer: Option E
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Bunuel
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