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08 Oct 2019, 23:44
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
66% (00:51) correct
34%
(00:48)
wrong
based on 231
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If x is 1, 2, or 3 and y is either 2 or 4, then the product xy can have how many different possible values?
A. Three
B. Four
C. Five
D. Six
E. Seven
A. Three
B. Four
C. Five
D. Six
E. Seven
Archit3110
Updated on: 09 Oct 2019, 10:49
Originally posted by Archit3110 on 09 Oct 2019, 10:06.
Last edited by Archit3110 on 09 Oct 2019, 10:49, edited 1 time in total.
Last edited by Archit3110 on 09 Oct 2019, 10:49, edited 1 time in total.
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Bunuel
x= 3 ' 3c1
and y = 2 ; 2c1
3c1*2c1 ' 6
since 1*4 and 2*2 = 4 so different possible values = 5
IMO C
09 Oct 2019, 10:43
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Archit3110
Dont we need to consider 1*4 and 2*2 as same solution?? If so, the answer will be 5.
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