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14 Oct 2019, 03:22
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
74% (01:49) correct
26%
(02:04)
wrong
based on 125
sessions
History
Date
Time
Result
Not Attempted Yet
If there are 16 people to choose from, what is the ratio of the number of possible 7-person committees to the number of possible 8-person committees?
(A) 7:8
(B) 8:7
(C) 7:9
(D) 8:9
(E) 9:8
(A) 7:8
(B) 8:7
(C) 7:9
(D) 8:9
(E) 9:8
14 Oct 2019, 05:33
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Bunuel
ratio of the number of possible 7-person committees to the number of possible 8-person committees = \(16c_7 : 16c_8\)
= \(\frac{16!}{(7!*9!)} : \frac{16!}{(8!*8!)}\)
= \(8!*8! = 7!*9!\)
= \(8*8! : 9!\)
= \(8 : 9\)
IMO Option D
Archit3110
14 Oct 2019, 08:49
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Bunuel
16c7/16c8 =
16!/7!9! *8!*8!/ 16!
solve
8:9
IMO D
