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28 Oct 2019, 22:02
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
94% (01:39) correct
6%
(02:55)
wrong
based on 171
sessions
History
Date
Time
Result
Not Attempted Yet
In a certain orchestra, each musician plays only one instrument and the ratio of musicians who play either the violin or the viola to musicians who play neither instrument is 5 to 9. If 7 members of the orchestra play the viola and four times as many play the violin, how many play neither?
(A) 14
(B) 28
(C) 35
(D) 63
(E) 72
(A) 14
(B) 28
(C) 35
(D) 63
(E) 72
28 Oct 2019, 22:51
Kudos
Bookmarks
Bunuel
Given: In a certain orchestra, each musician plays only one instrument and the ratio of musicians who play either the violin or the viola to musicians who play neither instrument is 5 to 9.
Asked: If 7 members of the orchestra play the viola and four times as many play the violin, how many play neither?
Musicians to play either the violin or the viola = 5x
musicians who don't play either the violin or the viola = 9x
Musicians who play viola = 7
Musicians who play violin = 7*4 = 28
Musicians who play either the violin or the viola = 35 = 5x ; x = 7
Musicians who play neither = 9x = 9*7 = 63
IMO D
29 Oct 2019, 00:40
Kudos
Bookmarks
Bunuel
Question : How many members play neither (N) ?
Given : \(\frac{Viola + Violin}{Neither}\) = \(\frac{5}{9}\) ---- (I)
Viola = 7
Violin = 7* 4 = 28
Use these nos. in equation (I)
\(\frac{7 + 28}{N}\)= \(\frac{5}{9}\)
Solving we get,
N = 63 (D)
